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GarryVolchara [31]
2 years ago
11

Students are selling pies for a school fundraiser. Customers can buy cherry pies and apple pies. Jennifer sold 12 cherry pies an

d 3 apple pies for a total of 144. Jacob sold 2 cherry pies and 9 apple pies for a total for 126
Mathematics
1 answer:
Tpy6a [65]2 years ago
7 0

Answer: A cherry pie costs 9 and an apple pie cost 12

Step-by-step explanation:

Let an apple pie be represented by a

Let an cherry pie be represented by c

Jennifer sold 12 cherry pies and 3 apple pies for a total of 144. This can be written as:

12c + 3a= 144

Jacob sold 2 cherry pies and 9 apple pies for a total for 126. This can be written as:

2c + 9a = 126

12c + 3a= 144 ............. i

2c + 9a = 126 ........... ii

Multiply equation i by 2

Multiply equation ii by 12

24c + 6a = 288 ........ iii

24c + 108a = 1512 ...... iv

Subtract iv from iii

-102a = -1224

a = 1224/102

a = 12

An apple pie costs 12

From equation i

12c + 3a= 144

12c + (3×12) = 144

12c + 36 = 144

12c = 144 - 36

12c = 108

c = 108/12

c = 9

A cherry pie costs 9

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Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1
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Answer:

x=4

Step-by-step explanation:

Given \displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1, start by squaring both sides to work towards isolating x:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2

Recall (a-b)^2=a^2-2ab+b^2 and \sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}:

\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1

Isolate the radical:

\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}

Square both sides:

\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2

Expand using FOIL and (a+b)^2=a^2+2ab+b^2:

\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36

Move everything to one side to get a quadratic:

\displaystyle-\frac{1}{4}x^2+7x-24=0

Solving using the quadratic formula:

A quadratic in ax^2+bx+c has real solutions \displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}. In \displaystyle-\frac{1}{4}x^2+7x-24, assign values:

\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24

Solving yields:

\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}

Only x=4 works when plugged in the original equation. Therefore, x=24 is extraneous and the only solution is \boxed{x=4}

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Answer:

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Step-by-step explanation:

Gina needs to cut two types of rectangles.

Dimensions of one rectangle is given as,

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So, the area of this rectangular paper will be

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