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GarryVolchara [31]
3 years ago
11

Students are selling pies for a school fundraiser. Customers can buy cherry pies and apple pies. Jennifer sold 12 cherry pies an

d 3 apple pies for a total of 144. Jacob sold 2 cherry pies and 9 apple pies for a total for 126
Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0

Answer: A cherry pie costs 9 and an apple pie cost 12

Step-by-step explanation:

Let an apple pie be represented by a

Let an cherry pie be represented by c

Jennifer sold 12 cherry pies and 3 apple pies for a total of 144. This can be written as:

12c + 3a= 144

Jacob sold 2 cherry pies and 9 apple pies for a total for 126. This can be written as:

2c + 9a = 126

12c + 3a= 144 ............. i

2c + 9a = 126 ........... ii

Multiply equation i by 2

Multiply equation ii by 12

24c + 6a = 288 ........ iii

24c + 108a = 1512 ...... iv

Subtract iv from iii

-102a = -1224

a = 1224/102

a = 12

An apple pie costs 12

From equation i

12c + 3a= 144

12c + (3×12) = 144

12c + 36 = 144

12c = 144 - 36

12c = 108

c = 108/12

c = 9

A cherry pie costs 9

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QUESTION 1

The given binomial is;

(x+9)(3x-4)

First terms are multiplied: x\times 3x=3x^2

Outside terms are multiplied: x\times -4=-4x

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Last terms are Multiplied: 9\times -4=-36

This gives us;

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QUESTION 2

We want to factor

6r^5s+4r^4s^2-8r^2s

The HCF is 2r^2s

We factor to get;

2r^2s(3r^3+2r^2s-4)

QUESTION 3;

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Split the middle term;

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Factor

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The solutions are;

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Answer:

The total number of students in a survey is 300.

Let the number of junior male(JM) be x and the number of senior males(SM) be y.

Let the number of junior female(JF) be p and the number of senior males(SF) be q.

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