All categories

3 years ago

A rectangle has a height of 5m^4 and a width of m^2-2m-1.

Mathematics

2 answers:

In-s [12.5K]3 years ago

8 0

Answer:

area of the rectangle = 5(m⁶ - 2m⁵ - m⁴) or 5m⁴(m² - 2m - 1)

Step-by-step explanation:

The rectangle has a height of 5m⁴ and the width is m² - 2m - 1.The area of the rectangle is the product of the width and the height.

width = m² - 2m - 1

height = 5m⁴

area of rectangle = 5m⁴ × (m² - 2m - 1)

area of rectangle = 5m⁴(m² - 2m - 1)

area of the rectangle = 5m⁶ - 10m⁵ - 5m⁴

area of the rectangle = 5(m⁶ - 2m⁵ - m⁴)

The area of the entire rectangle can be expressed as 5(m⁶ - 2m⁵ - m⁴) or 5m⁴(m² - 2m - 1)

Serhud [2]3 years ago

8 0

Answer:

5m^6-10m^5-5m^4

Step-by-step explanation:

You might be interested in

Which graft represent -3x+5y=-15

azamat

The graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

-3x + 5y = -15

The above function shows a linear function we can write it as:

5y = 3x - 15

y = (3x - 15)/5

If x = 0, y = -3

x = 1, y = -2.4

x = 2, y = -1.8

x = -1, y = -3.6

x = -2, y = -4.2

Thus, the graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

7 0

2 years ago

Help me please I need this for tomorrow please please

Andrews [41]

Need a better picture if u post it again soon I’ll see it and I’ll tell u

8 0

2 years ago

Read 2 more answers

How do you divide decimals

goblinko [34]

The same way you divide normal numbers, 0.5/0.5 = 1

3 0

3 years ago

Read 2 more answers

Find the equation of the line specified. The line passes through the points

marishachu [46]

Answer:

Step-by-step explanation:

substitute (2,1) and (5,4) into each equation

2-1=1 and 5-4=1 so c is correct

7 0

3 years ago

Read 2 more answers

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago