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3 years ago

What two pieces of information do you need to know to get from one location to another?

Physics

1 answer:

Tresset [83]3 years ago

6 0

That two information would be "Velocity" & "Time"

We Know = Displacement = Velocity * Time

Hope this helps!

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A 6.00 cm tall light bulb is placed a distance of 54.2 cm from a double convex lens

BigorU [14]

Answer:

1 / f = 1 / i + 1 / o thin lens equation

1 / i = 1 / f - 1 / o = (o - f) / (o * f)

i = o * f / (o - f)

i = 54.2 * 12.7 / (54.2 - 12.7) = 16.6 cm image distance

Image is real and inverted and 16.6 / 54.2 * 6 = 1.94 cm tall

7 0

3 years ago

In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 Hz passes through a pair of slits separated by 2.20 × 1

asambeis [7]

Explanation:

It is given that,

Frequency of monochromatic light, $f=5\times 10^{14}\ Hz$

Separation between slits, $d=2.2\times 10^{-5}\ m$

(a) The condition for maxima is given by :

$d\ sin\theta=n\lambda$

For third maxima,

$\theta=sin^{-1}(\dfrac{n\lambda}{d})$

$\theta=sin^{-1}(\dfrac{nc}{fd})$

$\theta=sin^{-1}(\dfrac{3\times 3\times 10^8\ m/s}{5\times 10^{14}\ Hz\times 2.2\times 10^{-5}\ m})$

$\theta=4.69^{\circ}$

(b) For second dark fringe, n = 2

$d\ sin\theta=(n+1/2)\lambda$

$\theta=sin^{-1}(\dfrac{5\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{5c}{2df})$

$\theta=sin^{-1}(\dfrac{5\times 3\times 10^8}{2\times 2.2\times 10^{-5}\times 5\times 10^{14}})$

$\theta=3.90^{\circ}$

Hence, this is the required solution.

8 0

3 years ago

Lionel makes a graphic organizer to compare the electric field around a positive charge with the electric field around a negativ

krek1111 [17]

X- points away from the charge
y- points in the direction of the force on the positive charge
z- points toward the charge

6 0

3 years ago

Read 2 more answers

Explain why the drill bit gets hot when it's turning in the wood

alexgriva [62]

The friction between the two objects creates heat.

3 0

3 years ago

Read 2 more answers

A blacksmith heats a 35 g lump of iron from room temperature until it glows (2425 degrees C) to work it. If the specific heat of

Drupady [299]

Answer:

37.9 kJ

Explanation:

We can calculate the thermal energy gained by the iron using the formula:

$Q=m C_s \Delta T$

where

m = 35 g is the mass of the iron

Cs = 0.450 j/g is the iron's specific heat capacity

$\Delta T= 2425 C - 20 C = 2405 C$ is the change in temperature of the iron (assuming that the room's temperature is 20 C degrees)

Substituting numbers into the formula, we find

$Q=(35 g)(0.450 J/g)(2405 C)=3.79\cdot 10^4 J=37.9 kJ$

6 0

3 years ago