Density of a Liquid:
Problem: You are given two unknown liquids. Find the density of each.
Materials: 100ml graduated cylinder, triple beam balance, calculator, 2 unknown liquids.
Procedure:
1) Find the mass of the empty graduated cylinder.
2) Pour unknown liquid #1 into the graduated cylinder to the 50 ml . level.
3) Find the mass of the graduated cylinder with 50ml of unknown liquid #1.
4) Repeat steps 1-3 for unknown liquid #2.
Answer:
According to newton's second law of motion F=ma, Data:-m=1800kg ,a=3m/sec² and F=? solution :-F=ma ,F=1800×3=5400kgm/s² or N (newton)
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Answer:
h₂ = 27.22m : height the pellet reaches
Explanation:
Pellet kinetics
Pellet moves with uniformly accelerated movement in
freefall
v f₁²=v₀²+2g*h₁ (formula 1) : ball movement down
v f₂²=v₀²-2g*h₂ (formula (formula 2) : ball movement up
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
g: acceleration due to gravity in m/s²
h :height in m
Known data
g=9.8 m/s²
h₁=12.7m
v f₁= 27.9 m/s
Initial velocity calculation (v₀)
We replace the data in formula 1:
27.9²=v₀²+2*9.8* 12.7
27.9²-2*9.8* 12.7=v₀²
529.49=v₀²
Calculation of the height that the pellet reaches when it goes up
Data:
v f₂=0 :When the pellet reaches the maximum height the final speed is zero
We replace the data in formula (2)
0²=23.1²-2*9.8*h₂
19.6h₂ =23.1²
h₂ =23.1²÷19.6
h₂ =27.22m
Answer:
The speed of water flow inside the pipe at point - 2 = 34.67 m / sec
Explanation:
Given data
Diameter at point - 1 = 3.2 cm
Velocity at point - 1 = 1.1 m / sec = 110 cm / sec
Diameter at point - 2 = 0.57 cm
Velocity at point - 2 = ??
We know that from the continuity equation the rate of flow is constant inside a pipe between two points.
Thus
⇒ × = ×
⇒ × × =
⇒ × = ×
⇒ × 110 = ×
⇒ = 3467 cm / sec
⇒ = 34.67 m / sec
Thus the speed of water flow inside the pipe at point - 2 = 34.67 m / sec