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max2010maxim [7]

2 years ago

14

4. The 50-kg crate shown in Fig. rests on a horizontal surface for which the coefficient of

1 answer:

laila [671]2 years ago

5 0

Answer:

5.057 m/s^2

Explanation:

Force of kinetic friction = .3 = F /normal force

.3 = F /(50* 9.81) F of friction = 147.15

Net force = 400 - 147.5 = 252.85 N

F = m * a

252.85 = 50 * a a = 5.057 m/s^2

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Which takes place as water cycles from the bottom of the pot towards the top

bagirrra123 [75]

I have no idea as well!

6 0

3 years ago

An instructor’s laser pointer produces a beam of light with a circular cross section of diameter 0.900 mm and a total power outp

il63 [147K]

Answer:

$E_0 = 2180.53N/C.$

$B_0 = 7.27*10^{-6}T.$

$U_{avg} = 4.2*10^{-5}J/m^3.$

Explanation:

The Intensity $I$ of the beam is

$I = P /A$

The diameter of the beam is 0.900mm; therefore, the area is

$A = \pi( \dfrac{0.900*10^{-3}}{2} )^2$

$A = 6.36*10^{-7}m^2$

and since $P = 4.00*10^{-3}W$ , the intensity of the beam is

$I = \dfrac{4.00*10^{-3}W}{6.36*10^{-7}m^2}$

$\boxed{I = 6289.3W/m^2.}$

Now, the intensity $I$ is related to $E_0$ by the relation

$I = \dfrac{E_0^2}{2\mu_0 c}$

solving for $E_0$ we get

$E_0 = \sqrt{2\mu_0 c I}$

putting in the numbers we get:

$E_0 = \sqrt{2(1.26*10^{-6}) (3*10^8) (6289.3)}$

$\boxed{E_0 = 2180.53N/C.}$

The amplitude of magnetic field $B_0$ is related to $E_0$ by

$B_0 = \dfrac{E_0}{c}$

putting in numerical values we get:

$B_0 = \dfrac{2180.53}{3*10^8}$

$\boxed{B_0 = 7.27*10^{-6}T. }$

The average energy density of the laser light is

$U_{avg} = \epsilon_0 E_0^2$

$U_{avg} = (8.85*10^{-12}) (2180.53)^2$

$\boxed{U_{avg} = 4.2*10^{-5}J/m^3.}$

8 0

4 years ago

Which was NOT a feature of welfare reform

qaws [65]

HeLLo tHeRe!

Your answer should be public transportation vouchers

Hope this helps. Have a nice day.

8 0

4 years ago

Problem 5 A block of mass 3 kg slides on a horizontal, rough surface towards a spring with k = 500 N/m. The kinetic friction coe

vredina [299]

Answer:

Explanation:

given,

mass of block = 3 kg

spring constant k = 500 N/m

kinetic friction coefficient µk = 0.6

speed of block = 5 m/s

F = µk N

F = 0.6 x 3 x 9.8

F = 17.64 N

using energy conservation

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2+Fx$

$\dfrac{1}{2}\times 3 \times 5^2=\dfrac{1}{2}\times 500 \times x^2+17.64\times x$

250 x² + 17.64 x - 37.5 = 0

on solving

x = 0.354 m

graph is attached below

4 0

4 years ago

Read 2 more answers

Give an example of a genotype for a person with brown hair. (brown is dominant)

nirvana33 [79]

Answer:

Bb can be an example

Explanation:

That is Because brown is dominated, so it is in Capital.

8 0

3 years ago