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3 years ago

Which expression is equivalent to 36x2 - 25?

Mathematics

1 answer:

Dimas [21]3 years ago

3 0

Answer:

The equivalent expression is: (6x + 5)*(6x - 5)

Step-by-step explanation:

This expression is called the difference of two squares.

It has the following format: $a^{2} - b^{2}$

It is factored as: $a^{2} - b^{2} = (a-b)*(a+b)$

In this question:

$a^{2} - b^{2} = 36x^{2} - 25$

$a^{2} = 36x^{2}$ , then $a = \sqrt{36x^{2}} = 6x$

$b^{2} = 25$ , then $b = \sqrt{25} = 5$

The equivalent expression is: (6x + 5)*(6x - 5)

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A ball is thrown in the air from a platform that is 96 feet above ground level with an initial vertical velocity of 32 feet per

pishuonlain [190]

Answer:

y = -16 (x - 1)^2 + 112

The object lands on the ground in approximately 3.6s

Explanation:

The equation given is that of a parabola.

Now the maximum (local) point of a parabola is the vertex. Therefore, if we want to rewrite our function in the form that would be used to find the maximum height, then that form must be the vertex form of a parabola.

The vertex form of a parabola is

$y=a(t-h)^2+k$

where (h, k) is the vertex.

The only question is, what is the vertex for our function h(t)?

Remember that if we have an equation of the form

$y=ax^2+bx+c$

then the x-coordinate of the vertex is

$h=-\frac{b}{2a}$

Now in our case b = 32 and a = -16; therefore,

$h=\frac{-32}{2(16)}=1$

We've found the value of the x-coordinate of the vertex. What about the y-coordinate? To get the y-coordinate, we put x = 1 into h(t) and get

$k=-16(1)+32(1)+96=112$

Hence, the y-coordindate is k = 112.

Therefore, the vertex of the parabola is (1, 112).

With the coordinates of the vertex in hand, we now write the equation of the parabola in vertex form.

$h(t)=a(t-1)^2+112$

The only problem is that we don't know what the value of a is. How do we find a?

Note that the point (0, 96) lies on the parabola. In other words,

$h(0)=-16(0)^2+32(0)+96=96$

Therefore, the vertex form of the parabola must also contain the point (0, 96).

Putting in t = 0, h = 96 into the vertex form gives

$96=a(0-1)^2+112$ $96=a+112$

subtracting 112 from both sides gives

$a=-16$

With the value of a in hand, we can finally write the equation of the parabola on vertex form.

$\boxed{h\mleft(t\mright)=-16\left(t-1\right)^2+112.}$

Now when does the object hit the ground? In other words, for what value of t is h(t) = 0? To find out we just have to solve the following for t.

$h(t)=0.$

We could either use h(t) = -16t^2 + 32t + 96 or the h(t) = -16(t - 1)^2 + 112 for the above equation. But it turns out, the vertex form is more convenient.

Thus we solve,

$-16\left(t-1\right)^2+112=0$

Now subtracting 112 from both sides gives

$-16(t-1)^2=-112$

Dividing both sides by -16 gives

$(t-1)^2=\frac{-112}{-16}$ $(t-1)^2=7$

taking the square root of both sides gives

$t-1=\pm\sqrt{7}$

adding 1 to both sides gives

$t=\pm\sqrt{7}+1$

Hence, the two solutions we get are

$t=\sqrt{7}+1=3.6$ $t=-\sqrt{7}+1=-1.6$

Now since time cannot take a negative value, we discard the second solution and say that t = 3.6 is our valid solution.

Therefore, it takes about 3.6 seconds for the object to hit the ground.

3 0

1 year ago

The answer to a subtraction problem

Ronch [10]

Answer:

The answer in a subtraction problem is called the difference.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Select all the factors roots of x^3 +2x^2-16x-32

Ivanshal [37]

Factor by grouping. Group up the terms into pairs, factor each pair, then factor out the overall GCF.

x^3 + 2x^2 - 16x - 32

(x^3 + 2x^2) + (-16x-32) ... pair up terms

x^2(x + 2) + (-16x - 32) ... factor x^2 from the first group

x^2(x + 2) - 16(x + 2) ... factor -16 from the second group

(x^2 - 16)(x + 2) .... factor out (x+2)

(x - 4)(x + 4)(x + 2) .... Use the difference of squares to factor x^2-16

---------------------------

The original expression completely factors to (x - 4)(x + 4)(x + 2)

The three factors are x - 4 and x + 4 and x + 2

5 0

3 years ago

Read 2 more answers

Fabulous fitness charges a one time fee of $90 and an additional $25 per month wonder weights charges a one time fee of only $ 2

Aleksandr-060686 [28]

Answer:

9 months

Step-by-step explanation:

Given

Fabulous fitness charges a one-time fee of $90 and an additional $25 per month

let the number of months be x

and the total charges be y

y= 25x+90---------1

Wonder weights charges a one-time fee of only $ 27 dollars but charge an additional $32 each month

let the number of months be x

and the total charges be y

y= 32x+27------------2

Required

The value of x, that is the number of months

Step two:

Equating both equations we have

25x+90=32x+27

collect like terms

25x-32x=27-90

-7x=-63

7x=63

divide both sides by 7

x= 63/7

x= 9 months

6 0

3 years ago

In the following triangle theta=60.Find the values of the angles of the angles B and B'

Contact [7]

Answer:

180-60 = 120 if triangle is not equilateral it cannot be isosceles then depending where the angles are they will show 60,60,60 if equilateral

For isosceles it would need to be 58 61 61 as 60, 60,60 cannot be isosceles.

Vectors 60 if right angled triangle = 90-60 = 30

So angles = 30 and 90 degree or just 120 if angle theta is a vector as explained below.

Step-by-step explanation:

Statement: If two vectors are represented by the sides of a triangle both in magnitude and direction taken in order, the resultant sum of the vectors is given by the closing third side of the triangle taken in the reverse order both in the magnitude and direction

5 0

3 years ago