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2 years ago

Meagan knits 1/10 of q scarf in 3/4 of annhour.What fraction of a scaf can megan knit in 1 hour

Mathematics

1 answer:

Nutka1998 [239]2 years ago

7 0

Answer:

2/15

Step-by-step explanation:

To solve this problem we just need to use a rule of three, relating the fraction of the scarf knitted and the amount of time.

So we have that:

1/10 of the scarf -> 3/4 hour

x of the scarf -> 1 hour

x * (3/4) = 1/10

x = (1/10) / (3/4)

x = (1/10) * (4/3)

x = 4/30 = 2/15

In one hour, Meagan knit 2/15 of the scarf.

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3 years ago

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Please solve the table correctly.

Hitman42 [59]

Answer:

See below.

Step-by-step explanation:

No. Triangles Perimeter

1 14

2 18

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We see from the table, after the first perimeter (= 14), with each increase of 1 in the number of triangles, the perimeter increases by 4.

As an equation it is P = 14 + 4(n - 1) where P = perimeter and n = number of triangles.

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3 years ago

What is the area of triangle DEF?

FrozenT [24]

Answer:

$A=2\sqrt{14}\ units^2$

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

$A=\sqrt{s(s-a)(s-b)(s-c)}$

where

a, b and c are the length sides of triangle

s is the semi-perimeter of triangle

we have

$a=5\ units,b=6\ units,c=3\ units$

<em>Find the semi-perimeter s </em>

s= $\frac{5+6+3}{2}=7\ units$

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$A=\sqrt{7(7-5)(7-6)(7-3)}$

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$A=\sqrt{56}\ units^2$

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3 0

2 years ago

Can someone help me plz .. Use these lengths to find cos B, tan B, and sin B.

lara [203]

Answer:

cos B = $\frac{7}{25}$

tan B = $\frac{24}{7}$

sin B = $\frac{24}{25}$

Step-by-step explanation:

In the right triangle, there are three sides and 2 acute angles

Hypotenuse ⇒ the opposite side of the right angle

Leg1 and Leg 2 ⇒ the sides of the right angle

The trigonometry functions of one of the acute angles Ф are

sin Ф = opposite leg/hypotenuse

cos Ф = adjacent leg/hypotenuse

tan Ф = opposite leg/adjacent leg

In Δ ACB

∵ ∠C is the right angle

∴ AB is the hypotenuse

∵ AC is the opposite side of ∠B ⇒ leg1

∵ CB is the adjacent side of ∠B ⇒ leg2

→ By using the ratios above

∴ cos B = $\frac{CB}{AB}$ , tan B = $\frac{AC}{CB}$ , sin B = $\frac{AC}{AB}$

∵ CB = 7, AB = 25, AC = 24

∴ cos B = $\frac{7}{25}$

∴ tan B = $\frac{24}{7}$

∴ sin B = $\frac{24}{25}$

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3 years ago

Calculate the area of the given quadrilaterals.

nadya68 [22]

Answer:

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(1/2)*(7+17)24

=288cm²

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2 years ago