The volume of 1 mole of gas is always 22.4 dm3. Molar volume= Volume/number of moles (first we should discover the number of mole) so 22.4 =1/number of moles <=> number of moles=1/22.4 moles
Now that we know the number of moles we can use the formula Molar Mass= mass /number of moles <=> 254= mass/(1/22.4) so mass =254/22.4 <=> mass= 11.339 which is 11.3 g
Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.
Explanation :
According to dilution law:

where,
= molarity of aqueous sodium carbonate
= molarity of aqueous sodium carbonate stock solution
= volume of aqueous sodium carbonate
= volume of aqueous sodium carbonate stock solution
Given:
= 1.00 M
= 1.58 M
= 575 mL
= ?
Now put all the given values in the above formula, we get:


Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.
C. NH3 (I looked it up, so sorry if it is wrong.)
Answer:
1.15 Kilo-joules are provided as electricity
Explanation:
The law of conservation of energy states that: "Energy can neither be created nor destroyed, but can convert from one form to another".
Applying this on the givens, we would find that:
driving energy = energy provided as electricity + energy lost as heat
2.75 = energy provided as electricity + 1.6
energy provided as electricity = 2.75 - 1.6 = 1/15 kilo-joules
Hope this helps :)
The neutralization reaction would be:
HCl + NaOH --> NaCl + H₂O
Next, determine the equivalent moles of HCl from the given amount of titrant. However, there is a missing information. You should know the molarity of the NaOH to be able to solve this. Suppose, the concentration is 0.1 M NaOH.
0.1 M NaOH * 0.3255 L = 0.03255 mol NaOH
Since, the molar ratio is 1:1, then that is also equivalent to 0.03255 mol HCl. The molarity would then be:
Molarity = 0.03255 mol/0.25 = <em>0.1302 M HCl</em>