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Monica [59]
3 years ago
12

Determine the direction of reaction if 1.00 M NOCl is combined with 0.500 M NO and 0.500 M Cl2 in a sealed flask. No reaction oc

curs. Reaction proceeds to the right toward the products. Reaction proceeds to the left toward the reactants. Reaction proceeds to the left toward the products.
Chemistry
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

Reaction proceeds to the left toward the reactants.

Explanation:

Hello,

In this case, since the reaction is:

2NOCl (g) \rightleftharpoons 2NO(g) + Cl_2 (g); Keq= 4.4 x10^{-4}

For the given amounts, one computes the reaction quotient:

Q=\frac{[NO]^2[Cl_2]}{[NOCl]^2} =\frac{(0.500M)^2(0.500M)}{(1.00M)^2} =0.125

Thus, since Q>Keq, the reaction will form more NOCl in order to increase its concentration and therefore reestablish the equilibrium, for that reason the answer is reaction proceeds to the left toward the reactants.

Regards.

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What is the solubility of methylacetylene (in units of grams per liter) in water at 25 °C, when the C3H4 gas over the solution h
Luda [366]

Answer:

The solubility of methylacetylene is 0,11 g L⁻¹

Explanation:

Henry's law is a gas law that states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid.

The formula is:

C = kH P

Where C is solubility of the gas (In mol/L)

kH is Henry constant (9,23x10⁻² mol L⁻¹ atm⁻¹)

An P is partial pressure (0,301 atm)

Solving, C = 2,78x10⁻³ mol L⁻¹. In grams per liter:

2,78x10⁻³ mol L⁻¹ₓ \frac{40 g}{mol} = <em>0,11 g L⁻¹</em>

<em></em>

I hope it helps!

7 0
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Evgesh-ka [11]
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4 0
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Find the volume in milliliters of 2.00 mol of an ideal gas at 36°C and a pressure of 1120 torr.
hram777 [196]

Answer:

V = 34430 mL

Explanation:

Given data:

Volume in mL = ?

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Solution:

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PV = nRT

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viktelen [127]
Lewis Structure is drawn in following steps,

1) Calculate Number of Valence Electrons:
    
# of Valence electrons in Mg  =  2
# of Valence electrons in I      =  7
# of Valence electrons in I      =  7
                                               ---------
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2) Draw Mg as a central atom surround it by two atoms of Iodine.

3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.

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4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.

The final lewis structure formed is as follow, 

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