There you go try that out.
What is a polyprotic buffer?
1 answer:
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Answer: The roll of lead (II) nitrate is that it is a limiting reactant of the reaction.
Solution : Given,
Molarity of = 0.1 M
Volume of = 50.0 ml = 0.05 L (1 L = 1000 ml)
Molarity of = 0.1 M
Volume of = 50.0 ml = 0.05 L
First we have to calculate the moles of and
.
The balanced chemical reaction is,
From the balanced chemical equation, we conclude that
3 moles of lead nitrate react with 2 moles of ferric chloride.
Thus 0.005 moles of lead nitrate react with moles of ferric chloride.
Moles of ferric chloride will be left unreacted = 0.005 - 0.0033 =0.0017 moles
Limiting reagent is the reagent in the reaction which limits the formation of product.
Excess reagent is the reagent in the reaction which is in excess and thus remains unreacted.
Therefore, in the given reaction, lead nitrate is the limiting reagent and ferric chloride is the excess reagent.
Answer:
37.1 kilograms of ammonia gas will be produced in this process
Explanation:
The percentage yield of the reaction is given by:
According to question
The percentage yield of the given industrial process = 74.0%
The given theoretical yield of ammonia gas = 50.1 kg
The experimental yield of ammonia gas = x
The percentage yield of the reaction is calculated a:
Solving for x, we get:
37.1 kilograms of ammonia gas will be produced in this process