Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
Explanation :
First we have to calculate the moles of 
Now we have to calculate the moles of 
The balanced chemical reaction is,
From the balanced chemical reaction we conclude that,
As, 1 mole of react to give 3 mole of
So, 
moles of react to give 
moles of
Now we have to calculate the mass of
Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
Solution with a ph of 7 Is neutral
Correct answer: B. Paleozoic. I took the test and it was right.
Answer :
121.5 <span>
μCi
Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.
We can use this formula;
</span>
3.8 /
=
((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5 </span>μci
Answer:
A model is developed for predicting oxygen uptake, muscle blood flow, and blood chemistry changes under exercise conditions. In this model, the working muscle mass system is analyzed. The conservation of matter principle is applied to the oxygen in a unit mass of working muscle under transient exercise conditions. This principle is used to relate the inflow of oxygen carried with the blood to the outflow carried with blood, the rate of change of oxygen stored in the muscle myoglobin, and the uptake by the muscle. Standard blood chemistry relations are incorporated to evaluate venous levels of oxygen, pH, and carbon dioxide.
Explanation:
