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uranmaximum [27]
3 years ago
9

What is the length of a 45 arc

Mathematics
2 answers:
Andru [333]3 years ago
8 0

Answer:

1.5707

Step-by-step explanation:

i solved it using the furmola :

2\pi \times r \frac{45}{360}

boyakko [2]3 years ago
4 0

Answer:

<h2>a = 1.57 in</h2>

Step-by-step explanation:

We know that the length of the arc in a circle is proportional to its corresponding angle which means:

a corresponds to 45

2πr corresponds to 360

then

\frac{a}{45} = \frac{2\pi r}{360}

then

a = (45÷360)×4×π

 =1.570796326795

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If X = 13 units, Y = 15 units, and h = 11 units, what is the area of the parallelogram shown above?
Sedbober [7]

Answer:

the area of the parallelogram = base times the height

For the given parallelogram :

x = 8 units, y = 13 units, and h = 11 units

1) If x is the perpendicular to h

So, the base = 8 and the height = 11

So, the area = 8 * 11 = 88 square units

2) If y is the perpendicular to h

So, the base = 13 and the height = 11

So, the area = 13 * 11 = 143 square units

Step-by-step explanation:

7 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
saw5 [17]

Hey there! :)

Answer:

First option: As x⇒ ∞ f(x) ⇒ -∞.  As x⇒ -∞ f(x) ⇒ ∞.

Step-by-step explanation:

Rearrange the equation:

f(x) = -x³ - 2x² + 1

This is a negative cubic function. The function decreases over the interval

(-∞, ∞). Therefore:

As x⇒ ∞ f(x) ⇒ -∞.

As x⇒ -∞ f(x) ⇒ ∞.

This is the first option.

4 0
3 years ago
Biught 820 books and 34 books on a shelf how many shelves
kramer
24.12 because you have to divide 34 into 820 and then you get 24.12
6 0
4 years ago
Question 14 (1 point)
valina [46]

Answer:

C(x) = 25 + 2x

Step-by-step explanation:

He already has 25 cards.

He is collecting 2 cards per month. In x months, he will have collected:

2 * x = 2x cards

That means that the number of cards he will have after x months will be the sum of the cards he already has and the cards he collects per month:

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8 0
3 years ago
10 points
Blababa [14]

Answer:

i think its A

Step-by-step explanation:

5 0
3 years ago
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