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Genrish500 [490]

3 years ago

10

Four whole numbers have been rounded to the nearest 10. The sum of the 4 rounded numbers 90. What is the maximum sum of the 4 or

iginal numbers ?

1 answer:

ziro4ka [17]3 years ago

3 0

Answer:

965 is the answer

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Please help me. 5(m-7)=-8(3m+8)

inessss [21]

Answer:

m = -1

Step-by-step explanation:

Solve for m:

5 (m - 7) = -8 (3 m + 8)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the left hand side:

5 m - 35 = -8 (3 m + 8)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

5 m - 35 = -24 m - 64

Hint: | Move terms with m to the left hand side.

Add 24 m to both sides:

24 m + 5 m - 35 = (24 m - 24 m) - 64

Hint: | Look for the difference of two identical terms.

24 m - 24 m = 0:

24 m + 5 m - 35 = -64

Hint: | Group like terms in 24 m + 5 m - 35.

Grouping like terms, 24 m + 5 m - 35 = (5 m + 24 m) - 35:

(5 m + 24 m) - 35 = -64

Hint: | Add like terms in 5 m + 24 m.

5 m + 24 m = 29 m:

29 m - 35 = -64

Hint: | Isolate terms with m to the left hand side.

Add 35 to both sides:

29 m + (35 - 35) = 35 - 64

Hint: | Look for the difference of two identical terms.

35 - 35 = 0:

29 m = 35 - 64

Hint: | Evaluate 35 - 64.

35 - 64 = -29:

29 m = -29

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 29 m = -29 by 29:

(29 m)/29 = (-29)/29

Hint: | Any nonzero number divided by itself is one.

29/29 = 1:

m = (-29)/29

Hint: | Reduce (-29)/29 to lowest terms. Start by finding the GCD of -29 and 29.

The gcd of -29 and 29 is 29, so (-29)/29 = (29 (-1))/(29×1) = 29/29×-1 = -1:

Answer: m = -1

7 0

3 years ago

The manufacturer of a CD player has found that the revenue R (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com

AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

$R(p) = -5p^2 + 1550p$

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

$\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550$

Equating the first derivative to zero, we get,

$\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155$

Again differentiation R(p), with respect to p, we get,

$\dfrac{d^2(R(p))}{dp^2} = -10$

At p = 155

$\dfrac{d^2(R(p))}{dp^2} < 0$

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

$R(155) = -5(155)^2 + 1550(155) = 120125$

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0

3 years ago

To prove ABC= ADC, To prove which triangle postulate could you use?

Kay [80]

Answer:

ASA

Step-by-step explanation:

..................

6 0

2 years ago

Read 2 more answers

HELP PLEASE. Check picture. I have tried but cannot seem to get it.

Sauron [17]

Answer:

$884^{-7}$

Step-by-step explanation:

Start by simplifying the denominator of the fraction. When multiplying exponents of the same base, you can add the exponents. This is also known as the product rule.

$a^x\cdot a^y=a^{x+y}$

["a" is the base, and "x" and "y" are the exponents]

Using this we find...

$884^{58}\cdot884^{46}=884^{58+46}=884^{104}$

When dividing exponents of the same base, you can subtract the exponents. This is also knows as the quotient rule.

$a^x\div a^y=a^{x-y}$

Using this we find...

$\frac{884^{97}}{884^{104}}=884^{97-104}=884^{-7}$

4 0

1 year ago

Read 2 more answers

X+6 for X=7<br><br> P/5 for p=30<br><br> 2x+y for x=5, y=4<br><br> Please Evaluate these.

AnnyKZ [126]

Answer:

13

6

14

Step-by-step explanation:

x+6=7+6=13

p/5=30/5=6

2x+y=2(5)+4=10+4=14

5 0

3 years ago