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White raven [17]
4 years ago
12

Marcus had 40$ until he earned $5.Find the percent of increase to the nearest whole percent

Mathematics
2 answers:
marissa [1.9K]4 years ago
8 0
It’s 13% I know bc I asked my mom
Rashid [163]4 years ago
7 0

Answer:

13%

Step-by-step explanation:

1% = $0.40

Therefore $5 = $5/$0.40=12.5% rounded up it is 13%

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Lines s and t are parallel. Find the value of x.<br> PLEASE HELPPPPP, THANKSS!!!!
MA_775_DIABLO [31]

Answer:

50 i think

Step-by-step explanation:

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3 years ago
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The figure shown is made up of a cone and a cylinder. The height of the cone is 5 ft and its diameter is 12 ft. The height of th
elena-s [515]

The lateral area of a cone is 147ft².

The total surface area of the cylinder is 867ft².

The total surface area is 1014ft²

<h3>What is the lateral surface area of a cone?</h3>

The lateral area of a cone is defined as the area covered by the curved surface of the cone.

Lateral area of a cone = πr x √(r² + h²)

Where:

  • r = radius = 12/2 = 6ft
  • h = height = 5ft
  • π = 3.14

3.14 x 6 x √(36 + 25) = 147ft²

<h3>What is the total surface area of the figure ?</h3>

Total surface area of the cylinder : πr(r + 2h),

(3.14 x 6) x (6 + 40) = 867ft²

Total surface area = 867 + 147=  1014ft²

To learn more about lateral surface area, please check: brainly.com/question/27847638

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4 0
2 years ago
Which sequence of transformations maps quadrilateral ABCD onto quadrilateral EFGH?
Elanso [62]

Answer:

Step-by-step explanation:

When you dilate something by a fraction the quadrilateral is going to get smaller. So, we can eliminate 2 and 4. Next I took point A and dilated it by 1/2 and then applied the translation to it. Once I figured out where each one landed, the first one was correct because it was on point E of EFGH and the other translation was not.

4 0
3 years ago
Robert is completing a construction of a square inscribed in a circle, as shown below. What should be the next step in his const
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3 0
3 years ago
The proof that AMNS AQNS is shown.
FrozenT [24]

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e   MS=SQ

In ΔMNS and ΔQNS

MN=QN       (∵ MNQ is isosceles triangle)

∠NMS=∠NQS     (∵ MNQ is isosceles triangle)

MS=SQ         (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

3 0
3 years ago
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