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Rus_ich [418]
2 years ago
9

Nuclear fusion please help :/

Chemistry
1 answer:
fiasKO [112]2 years ago
4 0

Answer:

  • The fuel for nuclear fusion is often uranium
  • Nuclear fusion is used to generate electricity at nuclear power plants

Explanation:

The most common nuclear fuel is made up of fissile elements such as Uranium, Neptunium, Plutonium,  Americium and  Curium, which are fissionable elements, which is when its nucleus is capable of undergoing a fission with neutrons free of any energy.

Nuclear fission can be used both for warlike purposes, as in the construction of atomic bombs, as well as for pacifist purposes, in the construction of reactors for the production of electrical energy.

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How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions
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Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V

Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V..[1]

Oxidation: anode

Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

E^o_{cell}=-0.036V-(-2.37 V)=2.334 V

The overall reaction will be:

2 × [1] + 3 × [2] :

2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-

Electrons on both sides will get cancelled :

2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

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