Answer:
34g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H2S + 2AgNO3 —> 2HNO3 + Ag2S
Next, we shall determine the number of mole of H2S required to react with 2 moles of AgNO3.
This is illustrated below:
From the balanced equation above,
We can see that 1 mole of H2S is required to react completely with 2 moles of AgNO3.
Finally, we shall convert 1 mole of H2S to grams. This is shown below:
Number of mole H2S = 1 mole
Molar mass of H2S = (2x1) + 32 = 34g/mol
Mass = number of mole x molar Mass
Mass of H2S = 1 x 34
Mass of H2S = 34g
Therefore, 34g of H2S is needed to react with 2 moles of AgNO3.
The substance has a higher density than water
What are your answer choices? Scientists express the weight in AMU’s so that they can easily think about the weight of the atom. If it is expressed in grams, they’re constantly dealing with a weight that’s around 10^-24 grams, which is hard to deal with.
Answer:
1.1 M
General Formulas and Concepts:
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define variables</u>
1.2 mol KCL
1.1 L of solution
M = unknown
<u>Step 2: Solve for Molarity</u>
- Substitute: M = 1.2 mol/1.1 L
- Evaluate: M = 1.09091
<u>Step 3: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules.</em>
1.09091 M ≈ 1.1 M
Explanation:
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