All categories

3 years ago

Write a balanced equation for the following reaction:

Chemistry

1 answer:

tiny-mole [99]3 years ago

6 0

Answer:

3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

The coefficients are 3, 1, 3, 1

Explanation:

From the question given above, the following data were:

Silver chloride reacts with sodium phosphate to yield sodium chloride and silver phosphate. This can be written as follow:

AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄

The above equation can be balanced as follow:

AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄

There are 3 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 3 in front of NaCl as shown below:

AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

There are 3 atoms of Cl on the right side and 1 atom on the left. It can be balance by putting 3 in front of AgCl as shown below:

3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

Thus, the equation is balanced.

The coefficients are 3, 1, 3, 1

You might be interested in

Sulfur and magnesium both have two valence electrons.<br> a. True<br> b. False

Nezavi [6.7K]

It would be false sulfur has 6

3 0

3 years ago

Is sulfur a metal, nonmetal, metalloid, or noble gas?

Blababa [14]

Sulfer is a nonmetal

6 0

2 years ago

A(n)____ is a ripened ovary

V125BC [204]

A(n) fruit is a ripened ovary

7 0

2 years ago

4.8 L sample of helium gas contains 0.22 moles of helium - How many additional moles of herum gas must be added to the sample to

yawa3891 [41]

Answer:

Explanation:

7 0

2 years ago

15.0 moles of gas are in a 8.00 L tank at 22.3 ∘C∘C . Calculate the difference in pressure between methane and an ideal gas unde

leva [86]

Answer:

$\Delta P=4.10atm$

Explanation:

Hello!

In this case, since the ideal gas equation is used under the assumption of no interaction between molecules and perfectly sphere-shaped molecules but the van der Waals equation actually includes those effects, we can compute each pressure as shown below, considering the temperature in kelvins (22.3+273.15=295.45K):

$P^{ideal}=\frac{nRT}{V}=\frac{15.0mol*0.08206\frac{atm*L}{mol*K}*295.45K}{8.00L}=45.5atm$

Next, since the VdW equation requires the molar volume, we proceed as shown below:

$v=\frac{8.00L}{15.0mol}=0.533\frac{L}{mol}$

Now, we use its definition:

$P^{VdW}=\frac{RT}{v-b} -\frac{a}{v^2}$

Thus, by plugging in we obtain:

$P^{VdW}=\frac{0.08206\frac{atm*L}{mol*K}*295.45K}{0.533mol/L-0.0430L/mol} -\frac{2.300L^2*atm/mol^2}{(0.533L/mol)^2}\\\\P^{VdW}=49.44atm-8.09atm\\\\P^{VdW}=41.4atm$

Thus, the pressure difference is:

$\Delta P=45.5atm-41.4atm\\\\\Delta P=4.10atm$

Best regards!

6 0

3 years ago