Classify the reaction: N2 (g) + 3H2 (g) à 2NH3 (g)

1 answer:

4 0

For the reaction N2(g) + 3H2(g) <=> 2NH3(g),
we have two reactants combining to form a single product. This type of reaction is called a Synthesis reaction.

(Quick side note): Because this is a reversible, you could write it in the opposite direction as a decomposition reaction.

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Which of the following two conditions will favor a spontaneous reaction?

Alexxx [7]

Answer:

option A

an increase in entropy and a decrease in enthalpy

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2 years ago

What is the mass of 0. 513 mol Al2O3? Give your answer to the correct number of significant figures. (Molar mass of Al2O3 = 102.

Margarita [4]

The mass of a 0.513 mol of Al2O3 is 52.33g.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the molar mass of the substance by its number of moles. That is;

mass of Al2O3 = no. of moles of Al2O3 × molar mass of Al2O3

According to this question, there are 0.513 moles of Al2O3.

Mass of Al2O3 = 0.513 × 102

Mass of Al2O3 = 52.33g

Therefore, the mass of a 0.513 mol of Al2O3 is 52.33g.

Learn more about mass calculations at: brainly.com/question/8101390?referrer=searchResults

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2 years ago

Is CH3NH2O ionic or covalent

Ivahew [28]

Answer:

i think ionic?

Explanation:

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1 year ago

How many molecules of aspartame are present in 1.00 mg of aspartame?

kobusy [5.1K]

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0.2 x 10^19

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2 years ago

If 16.00 g of O₂ reacts with 80.00 g NO, how many the excess reactant are left over? (enter only the value, round to whole numbe

pishuonlain [190]

Answer:

Explanation:

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 30.01 32.00 46.01

2NO + O₂ ⟶ 2NO₂

Mass/g: 80.00 16.00

2. Calculate the moles of each reactant

$\text{moles of NO} = \text{80.00 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{2.666 mol NO}\\\\\text{moles of O}_{2} = \text{16.00 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.5000 mol O}_{2}$