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3 years ago

Classify the reaction: N2 (g) + 3H2 (g) à 2NH3 (g)

1 answer:

4 0

For the reaction N2(g) + 3H2(g) <=> 2NH3(g),
we have two reactants combining to form a single product. This type of reaction is called a Synthesis reaction.

(Quick side note): Because this is a reversible, you could write it in the opposite direction as a decomposition reaction.

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3 years ago

620 mL of nitrogen at standard pressure is compressed into a 480 mL container. What is the new pressure in kPa?

bulgar [2K]

Answer:

c. 131 kPa

Explanation:

Hello!

In this case, since the relationship between volume and pressure is inversely proportional, based on the Boyle's law:

$P_1V_1=P_2V_2$

Considering that the standard pressure is 101.325 kPa, we can compute the final pressure as shown below:

$P_2=\frac{P_1V_1}{V_2}=\frac{620mL*101.325kPa}{480mL}\\\\P_2=131kPa$

Therefore, the answer is c. 131 kPa .

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3 years ago

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Galina-37 [17]

They are arranged by their atomic mass.

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3 years ago

The equilibrium constant has been estimated to be 0.12 at 25 °C. If you had originally placed 0.069 mol of cyclohexane in a 2.8

scZoUnD [109]

Answer: Concentrations of cyclohexane and methylcyclopentane at equilibrium are 0.0223 M and 0.0027 M respectively

Explanation:

Moles of cyclohexane = 0.069 mole

Volume of solution = 2.8 L

Initial concentration of cyclohexane = $\frac{moles}{Volume}=\frac{0.069}{2.8}=0.025M$

The given balanced equilibrium reaction is,

cyclohexane ⇔ methylcyclopentane

Initial conc. 0.025 M 0

At eqm. conc. (0.025-x)M (x) M

The expression for equilibrium constant for this reaction will be,

K= methylcyclopentane / cyclohexane

Now put all the given values in this expression, we get :

$0.12=\frac{(x)}{(0.025-x)}$

By solving the term 'x', we get :

x = 0.0027

Concentration of cyclohexane at equilibrium = (0.025-x ) M = (0.025-0.0027) M = 0.0223 M

Concentration of methylcyclopentane at equilibrium = (x ) M = (0.0027) M

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3 years ago