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2 years ago

Thank you!!! ;0;

Chemistry

1 answer:

Sati [7]2 years ago

7 0

Answer:

Kc ≅ 100 (1 sig. fig.)

Explanation:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

C(i) 3.00 mol/L 0 0

ΔC -2x +x +3x

C(eq) 0.600 mol/L x 3x

3.00 - 2x = 0.600 => x = 3.00 - 0.600/2 = 1.2 mole/L

At equilibrium Kc = [N₂][H₂]³/[NH₃]² = (x)(3x)³/(3·1.2)² = (1.2)(3.6)³/(0.600)² = 155.52 (calculator)

Rounds to 1 sig. fig. based on given 3.00 moles NH₃(g)' Kc ≅ 100.

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