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3 years ago

It was estimated that 825 people would attend the soccer game, but 817 people actually attended.

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

4 0

Answer:

$\frac{actual \: no- estimated \: no}{actual \: no} \times 100 \\ \frac{825 - 817}{825} \times 100 \\ \frac{8}{825} \times 100 \\ \frac{800}{825} \\ \frac{32}{33} \\ 0.96\%$

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Solving an Equation for a Given Variable

Reil [10]

Answer:

$a=\frac {f-v}{t}$

Step-by-step explanation:

f=v+at

It requires you to make a the subject of the formula

f-v=at

Dividing both sides by t then

$a=\frac {f-v}{t}$

Therefore, the equivalent for a is $a=\frac {f-v}{t}$

8 0

2 years ago

A veterinarian weighs three cats. The American Shorthair weighs 13.65 pounds. The Persian weighs 13.07 pounds, and the Maine Coo

Alex_Xolod [135]

Answer:

Persian, Maine Coon, American Shorthair

13.07, 13.6, 13.65

Step-by-step explanation:

I hope this helped!

7 0

2 years ago

A bacteria culture starts with 12,000 bacteria and the number doubles every 50 minutes.

Vlada [557]

Answer:

a) $y=12000(2)^{\frac{t}{50}}$

b) Approx. 27,569 bacteria

c) About 103 minutes

Step-by-step explanation:

This will follow exponential modelling with form of equation shown below:

$y=Ab^{\frac{t}{n}}$

Where

A is the initial amount (here, 12000)

b is the growth factor (double, so growth factor is "2")

n is the number of minutes in which it doubles, so n = 50

Substituting, we get our formula:

$y=Ab^{\frac{t}{n}}\\y=12000(2)^{\frac{t}{50}}$

To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.

Remember, t is in minutes, so

1 hour = 60 minutes

t = 60

Substituting, we get:

$y=12000(2)^{\frac{t}{50}}\\y=12000(2)^{\frac{60}{50}}\\y=12000(2)^{\frac{6}{5}}\\y=27,568.76$

The number of bacteria after 1 hour would approximate be <u>27,569 bacteria</u>

<u></u>

To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

$y=12000(2)^{\frac{t}{50}}\\50,000=12,000(2)^{\frac{t}{50}}\\4.17=2^{\frac{t}{50}}\\Ln(4.17)=Ln(2^{\frac{t}{50}})\\Ln(4.17)=\frac{t}{50}*Ln(2)\\\frac{t}{50}=\frac{Ln(4.17)}{Ln(2)}\\\frac{t}{50}=2.06\\t=103$

After about 103 minutes, there will be 50,000 bacteria

4 0

3 years ago

Solve using square roots

blsea [12.9K]

You can not see the problem

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3 years ago

A technician charges P 400 per hour and spends P 500 a day on gasoline. Write an alcat expression to represent his earnings for

Basile [38]

Answer:

y=400*x-500

Step-by-step explanation:

The expression that represents the problem is:

y=400*x-500

Function y represents earnings for one day.

400 is the fixed number that is charge for one hour work

x represents the number of hours that the technician has worked for one day

To find the total earnings you should multiply the fixed charge for one hour work (400) by the number of hours worked in a day.

Then you need to substract the cost of gasoline in a day, it is 500 and it is a constant in the equation since it doesn't depend on the number of hours worked.

So, the function is:

y=400*x-500

4 0

2 years ago