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Elena-2011 [213]
3 years ago
5

Let m=x²-5. which equation is equivalent to (x²-5)²-3x²+15=-2 in term of m?

Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0
The answer would be m^2+3m+2=0 because the first “part” of the equation (x^2-5) is equal to m; in the equation it’s squared so it can be replaced by m^2. next, 3m is the same as 3(x^2+5) which is what you have when you see 3x^2+15. finally, you have to bring the -2 over from the other side so you have positive 2. hope this helps!
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Q5: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.
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Answer:

d.\:ellipse;\:3x^2+y^2+6x-6y+3=0.

Step-by-step explanation:

The given conic has equation;

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\Rightarrow \frac{3x^2}{9}+\frac{y^2}{9}=\frac{9}{9}

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This is an ellipse centered at the origin;

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(-1,3)

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Clear the fraction;

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Expand;

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Write in general form;

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Answer:

4

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