V^2-6v+ complete square?

1 answer:

3 0

The answer is v² - 6v + 9.

Explanation:

To form perfect square:
v² - 6v

= v² - 6v + (6/2)²

= v² - 6v + (3)²

= v² - 6v + 9

Hope it helps!

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Alja [10]

Answer:The solution is in the attached file

Step-by-step explanation:

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Kamila [148]

Answer:

C. -11,325

Step-by-step explanation:

To know the answer, is convenient to replace some values of "n" in the sum $\sum_{(n=1)}^{150}[-1-(n-1)]$ .

The result would appear after adding up every value of the expression $\sum_{(n=1)}^{150}[-1-(n-1)]$ when n=1,2,3.....,150.
When n=1, the expression takes the value of (-1): $[-1-(1-1)]= (-1)-0=-1$ .
When n=2, the expression takes the value of (-2): $[-1-(2-1)]=-1-1=-2$ .
Following this way, for every n, we will obtain -n, then, the sum will be: $-1-2-3-4-5-6-...-150$ . This sum can actually be expressed as $\sum_{n=1}^{150}(-n)$ , which is the result of solving the initial expression of the sum $-1-(n-1)=-1-n+1=-n$ .
Finally, the sum of n=-1 to n=-150 equals -11,325.