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vampirchik [111]
3 years ago
7

Need some help with a few consecutive integer word problems, tysm if you do :)

Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Answer:

Answers are: A,D, and  A

Step-by-step explanation:

I hope these are right

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Solve each equation by completing the square 2q^2+8q=3
3241004551 [841]

Answer:

Divide by 2

q^2+4q=3/2

q^2+4q(4/2)^2=3/2+(4/2)^2

(q+4/2)^2=3/2+16/4

taking the square root of both side

√(q+4/2)^2=√(3/2+16/4)

Note that the square will cancel the square root then you will take LCM on the right hand side

q+4/2=√6+16/4

q+4/2=√22/4

q= -4/2+-√22/4

q=(-4+_√22/4)

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3 years ago
How would I use factoring to write equivalent expressions for the following expressions?
Sedbober [7]

Answer:

4(a + 6)

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Step-by-step explanation:

Factoring is just rewriting an expression into the parts that multiply together to make the original...like if I had a 100 but decided instead to write 4×25 or if I had 25x I wrote 5(5x) .

If you look at your

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You're looking for whatever is the same in both pieces (the 4a and also the 24) So there is a 4 in 4a and there is also a 4 "in" 24 (as in 4×6 is 24)

So if you pull out that 4 and throw it up front, whatever is left behind goes into a pair of parentheses.

4 (____ + ____)

4(a + 6)

This is your factored form bc if you multiply that 4 back in you'll get the original expression back again.

4a + 24

= 4(a + 6)

It's like factoring is "un-distributive" property.

Theres a 3 in 3x and also in 12

3x - 12

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6 0
2 years ago
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