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AysviL [449]
3 years ago
12

The value in dollars v(x), of a certain truck after x years is represented by the equation v(x)= 32,500(0.92) raised to the x po

wer. To nearest dollar, how much is the truck worth after 2 years than after three years
Mathematics
1 answer:
s2008m [1.1K]3 years ago
8 0
The 32,500 is the original cost of the truck and the (0.92) You take v(x)=32,500(0.92)
 and raise that to the 2nd power, to represent the 2nd year and you will get an answer of $27,300. 
Each year the truck is losing $2,600 in value, after two years the truck has lost $5,200 in value equalling
= $27,300

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3 years ago
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Answer: Deal one: y = 8.99x + 5 Deal two: y = 6

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2 years ago
Suppose A,B and C are 2 ×2 matrices , E,F and G are 3 × 3 matrices, H and K are 2×3 matrices and L and M are 3×2 matrices. For e
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Answer:

a) 2x2 b)3x3 c) Not possible d) 2x3 e) 3x2 f) 3x3 g)Not possible h)3x2

Step-by-step explanation:

-> we can only add matrices with same size

-> we can only multiply when columns of first equal to rows of second

-> nxm multiplied by pxq gives nxq eg 3x2 mul 2x2 gives 3x2

-> addition and mul by const number dont change the size

So considering the above facts :-

a) AB+C = [(2x2)(2X2)]+(2x2)=(2x2)+(2x2)=2x2

b) 3GF =3[(3x3)(3x3)]=3(3x3)=3x3

c)CK+B= [(2x2)(2x3)]+(2x2)=(2x3)+(2x2) which is not possible (see point 1)

d)CK+H =as CK is (2x3) so (2x3)+(2x3)=(2x3)

e)EMC=[(3x3)(3x2)](2x2)=(3x2)(2x2)=3x3

f)GLH=[(3x3)(3x2)](2x3)=(3x2)(2x3)=3x3

g)HLG=[(2x3)(3x2)](3x3)=(2x2)(3x3)= not possible(see point 2)

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8 0
3 years ago
Solve the following equations. Round your answers to the nearest hundredth as needed.
Mekhanik [1.2K]

Answer:

b = 1.31

Step-by-step explanation:

Step 1: Add 1.93 to both sides.

  • 9.13b-1.93+1.93=10.05+1.93
  • 9.13b=11.98

Step 2: Divide both sides by 9.13.

  • (9.13b)/9.13 = 11.98/9.13
  • b = 1.31215..

Step 3: Round to the nearest hundredth.

  • 1.31215.. ≈ 1.31

Therefore, b = 1.31.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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