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AysviL [449]
3 years ago
12

The value in dollars v(x), of a certain truck after x years is represented by the equation v(x)= 32,500(0.92) raised to the x po

wer. To nearest dollar, how much is the truck worth after 2 years than after three years
Mathematics
1 answer:
s2008m [1.1K]3 years ago
8 0
The 32,500 is the original cost of the truck and the (0.92) You take v(x)=32,500(0.92)
 and raise that to the 2nd power, to represent the 2nd year and you will get an answer of $27,300. 
Each year the truck is losing $2,600 in value, after two years the truck has lost $5,200 in value equalling
= $27,300

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W are r are not valid grades. I have attached the table associated with this question

Answer:
GPA = 3.625

Explanation:
GPA stands for "Grade Point Average".
It can be easily calculated by dividing the total grade points with the total number of hours.
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Hope this helps :)

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3 years ago
How many whole servings of 3/4 cups are in 31/2 cups of ice cream?
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6 0
3 years ago
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\int\frac{10}{(x-1)(x^2+9)}\ dx=(*)\\\\\frac{10}{(x-1)(x^2+9)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+9}=\frac{A(x^2+9)+(Bx+C)(x-1)}{(x-1)(x^2+9)}\\\\=\frac{Ax^2+9A+Bx^2-Bx+Cx-C}{(x-1)(x^2+9)}=\frac{(A+B)x^2+(-B+C)x+(9A-C)}{(x-1)(x^2+9)}\\\Updownarrow\\10=(A+B)x^2+(-B+C)x+(9A-C)\\\Updownarrow\\A+B=0\ and\ -B+C=0\ and\ 9A-C=10\\A=-B\ and\ C=B\to9(-B)-B=10\to-10B=10\to B=-1\\A=-(-1)=1\ and\ C=-1

(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1

\#2\ \int\frac{x}{x^2+9}\ dx\Rightarrow  \left|\begin{array}{ccc}x^2+9=u\\2x\ dx=du\\x\ dx=\frac{1}{2}\ du\end{array}\right|\Rightarrow\int\left(\frac{1}{2}\cdot\frac{1}{u}\right)\ du=\frac{1}{2}\int\frac{1}{u}\ du\\\\\\=\frac{1}{2}ln(u)+C_2=\frac{1}{2}ln(x^2+9)+C_2

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\boxed{=ln(x-1)-\frac{1}{2}ln(x^2+9)-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C}



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He wont have any to his self
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The expanded form for 300684 can be written with only 4 add ends. Explain how this is possible for a number with 6 digits
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Answer:

This can be because our number, 300,684, has only four digits different than zero.

Then we can write this number as:

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So we add only 4 terms.

So when we write a number in this form, we will have the same numbers of terms in the addition that the number of digits different than zero in our original number.

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