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qwelly [4]
3 years ago
9

Please help!!

Chemistry
1 answer:
Oksana_A [137]3 years ago
3 0
8g:20g. 12g:x
8/20 =12/x solve for x
X=30
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a student balanced the chemical equation for the reaction of magnesium with oxygen by writing Mg + O2 ----> MgO2. What is wro
egoroff_w [7]

Answer:

Explanation:

Magnesium when it oxidizes has a valence of 2.

Oxygen, when it mixes with something, has a valence of - 2

So Mg and O2 will form something, but what? The answer is MgO

Mg + O2 ===> MgO

To balance this equation, you need 2 Magnesiums on the right and 2 Oxygens also on the right. The left will need a  two Magnesiums.

The balanced equation will be

2Mg + O2 ====> 2MgO

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4 years ago
Which of the following is the balanced chemical equation for photosynthesis?
LuckyWell [14K]
The first one, <span>6H2O + 6CO2 → 6O2 + C6H12O6 is.</span>
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4 years ago
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What is the molar mass of the imaginary compound Z(AX3)2
astra-53 [7]

The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.

<h3>How do we calculate molar mass?</h3>

Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.

Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:

Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)

Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.

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7 0
2 years ago
What is the relationship between particle size and wheathering rate
Olegator [25]

The relationship between particle size and wethering rate as the errosion occurs on the surface area.

So wethering is proportional to the particles size of elements as more smaller the particles and more swiftly particles are surrounded erosion specially chemical occurrs weathering that acts as more aspace in rocks with small particle sizes.

5 0
4 years ago
If 34.5 g of Copper reacts with 70.2 g of silver nitrate, according to the following
Vlada [557]

Answer:

44,55 can be produced.

Explanation:

First, we balanced the equation

1Cu + 2AgNO3 → 1Cu(NO3)2 + Ag

Then, we find the moles of each reagent

mol Cu = \frac{34,5g}{63,55\frac{g}{mol} } = 0,543 mol\\

mol AgNO3 = \frac{70,2g}{169,87\frac{g}{mol} } = 0,413 mol\\

Now, we find the limiting reagent from the quantities of product that can be formed from each reagent

mol AgNO3= 0,543mol Cu . \frac{2 mol AgNo3}{1 mol Cu} = 1,086 mol

mol Cu= 0,413 mol AgNO3 . \frac{1 mol Cu}{2 mol AgNO3} = 0,206 mol

1,086 moles of AgNO3 is necessary for each mole of Cu since we have 0.413 moles of Ag(NO3), the nitrate is the limiting reagent

the value of the limiting reagent determines the amount of product that is generated

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Ag≈ 44,6g

4 0
4 years ago
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