Answer:
Explanation:
Magnesium when it oxidizes has a valence of 2.
Oxygen, when it mixes with something, has a valence of - 2
So Mg and O2 will form something, but what? The answer is MgO
Mg + O2 ===> MgO
To balance this equation, you need 2 Magnesiums on the right and 2 Oxygens also on the right. The left will need a two Magnesiums.
The balanced equation will be
2Mg + O2 ====> 2MgO
The first one, <span>6H2O + 6CO2 → 6O2 + C6H12O6 is.</span>
The molar mass of the imaginary compound Z(AX₃)₂ is the sum of the molar mass of Z, A and X.
<h3>How do we calculate molar mass?</h3>
Molar mass of any compound will be calculated by adding the mass of each atoms present in that compound.
Given compound is Z(AX₃)₂, molar mass of the given compound will be calculated as:
Molar mass of Z(AX₃)₂ = Molar mass of Z + molar mass of 2(A) + molar mass of 6(X)
Hence molar mass of Z(AX₃)₂ is the sum of the masses of all atoms.
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The relationship between particle size and wethering rate as the errosion occurs on the surface area.
So wethering is proportional to the particles size of elements as more smaller the particles and more swiftly particles are surrounded erosion specially chemical occurrs weathering that acts as more aspace in rocks with small particle sizes.
Answer:
44,55 can be produced.
Explanation:
First, we balanced the equation
1Cu + 2AgNO3 → 1Cu(NO3)2 + Ag
Then, we find the moles of each reagent
Now, we find the limiting reagent from the quantities of product that can be formed from each reagent
1,086 moles of AgNO3 is necessary for each mole of Cu since we have 0.413 moles of Ag(NO3), the nitrate is the limiting reagent
the value of the limiting reagent determines the amount of product that is generated
∴ 0,413 mol of Ag can be produced
Ag = 
= 44,55g
Ag≈ 44,6g
