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ser-zykov [4K]
2 years ago
12

Need help ASAP! Thank you so much for the help

Chemistry
2 answers:
aalyn [17]2 years ago
7 0
I think the correct answer is B. An example of gene therapy is when a defective gene is replaced with a normal gene.
Elena-2011 [213]2 years ago
4 0
The answer would be… B

Hope this helps!!
You might be interested in
Please help! Chemistry 113 smartworks question. Thanks !!!
Dominik [7]
Kc' =Kc^1/3
=3√0.0061
=0.182716013
3 0
3 years ago
If the elastic modulus of cobalt (co) is 200 gpa, and the elastic modulus of tungsten carbide (wc) is 700 gpa, calculate the upp
Dmitry_Shevchenko [17]
To determine the upper bond
Ec(u) = EmVm + EpVp
Em is the elastic modulus of cobalt.
E₁ is the elastic modulus of the particulate
Vm is the volume fraction of cobalt
Vp is the volume fraction of particulate
substitute
Ec(u) = 200 (Vm) + 700 (Vp)
To determine the lower bound
Ec (l) = EmEp/VmEp+ VpEm
Substitute
Ec (l) = 200(700)/Vm(700) + Vp (200)
Ec (l) = 1400/7Vm+2Vp
7 0
3 years ago
Take a cup of water, add sugar, and stir. if the resulting solution contains sugar crystals that do not dissolve, the solution i
Strike441 [17]
When a solvent has as much of the dilute dissolved in it as possible, then it is saturated.

If you were to heat the water, its capacity would increase and would then be super-saturated because it has more dissolved in it than possible as room temp.

Since there is no heating being done, the water is just saturated.

Hope that helps!
6 0
3 years ago
Pls help me.<br>.<br>.<br>click the pic​
uranmaximum [27]

Answer:

Gas - Fuel

Ethanol - Fuel

Acetone - Cleaner

LPG - Fuel

Kerosene - Fuel

Acetic Acid - Food

Explanation:

Source: Trust me bro!

GL, have a good one.

8 0
2 years ago
Given the following UNBALANCED reaction: NH3 (g) &lt;--&gt; N2 (g) + H2 (g) If 1
Yakvenalex [24]

Answer:

C. 1.35

Explanation:

                                                     2NH3 (g) <-->          N2 (g) +             3H2 (g)

Initial concentration                2.2 mol/0.95L       1.1 mol/0.95L           0

change in concentration        2x                             x                           3x

                                                 -0.84 M                  +0.42M                +1.26M

Equilibrium                       1.4 mol/0.95L=1.47M        1.58 M                   1.26 M

concentration

Change in concentration(NH3) = (2.2-1.4)mol/0.95 L = 0.84M

Equilibrium concentration (N2) = 1.1/0.95 +0.42=1.58 M

Equilibrium concentration(NH3) = 1.4/0.95 = 1.47M

K = [N2]*{H2]/[NH3] = 1.58M*1.26M/1.47M = 1.35 M

8 0
2 years ago
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