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RSB [31]
3 years ago
11

What are the products of this chemical equation? HCl(aq) + NaOH(aq) → NaCl(aq) + H2(g) + O2(g) NaH(aq) + Cl2(aq) + H2(g) + O2(g)

Cl2(g) + H2(g) + O2(g) NaCl(aq) + H2O(l)
Chemistry
2 answers:
Iteru [2.4K]3 years ago
7 0

Answer:

The correct answer is:

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

Explanation:

When aqueous solution of hydrogen chloride reacts with aqueous solution of sodium hydroxide to give aqueous solution of sodium chloride and water.

HCl(aq) + NaOH(aq)\rightarrow NaCl(aq)+H_2O(l)

1 mole of hydrogen chloride reacts with 1 mol of sodium hydroxide to give 1 mole of sodium chloride and 1  mole of water.

Hatshy [7]3 years ago
5 0
NaOH(aq) + HCl(aq) ----> NaCl(aq) + H₂O(l)

:•)
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Consider the following voltaic cell:(j) In which direction do anions within the salt bridge move to maintain charge neutrality?
aniked [119]

In order to maintain neutrality, the negatively charged ions in the salt bridge will migrate into the anodic half-cell. A similar (but reversed) situation is found in the cathodic cell.

<h3>What purpose does a salt bridge serve in an oxidation process?</h3>

Anions (negatively charged particles) are added to the solution of the oxidation half of the cell by the salt bridge, and cations (positively charged particles) are added to the solution of the reduction half of the reaction. 

<h3>What purpose does the salt bridge serve in a galvanic cell?</h3>

For instance, KCl, AgNO3, etc. In a galvanic cell, such as a voltaic cell or Daniel cell, salt bridges are typically used. A salt bridge's primary job is to assist in preserving the electrical neutrality of the internal circuit. Additionally, it aids in keeping the cell's response from reaching equilibrium.

Learn more about Salt bridge here:-

brainly.com/question/20345420

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7 0
1 year ago
Calculate the average reaction rate expressed in moles h2 consumed per liter per second
djyliett [7]

Answer:

Average rate of reaction expressed in moles H₂ consumed per liter per second = 0.0025 M/s = 0.0025 mol/L.s

Explanation:

The complete, correct Question, is presented in the attached image to this answer.

The average rate of reaction in terms of the reactant is defined as the total amount of reactant consumed over a period of time divided by total period of time.

Mathematically,

Average rate of reaction = (change in concentration of H₂ over a period of time) ÷ (total period of time)

Average rate of reaction = (-ΔC)/(Δt)

The minus sign is there because the concentration of reactants reduce with time.

change in concentration of H₂ = -ΔC

= -(0.02 - 0.03) = 0.01 M

Time = Δt = 4 - 0 = 4.0 s

Average rate of reaction = (0.01/4) = 0.0025 M/s

We could solve for the average rate of reaction expressed in moles Cl₂ consumed per liter per second

change in concentration of Cl₂ = -ΔC

= -(0.04 - 0.05) = 0.01 M

Time = Δt = 4 - 0 = 4.0 s

Average rate of reaction = (0.01/4) = 0.0025 M/s = 0.0025 mol/L.s

Hope this Helps!!!

8 0
3 years ago
The energy of a pendulum is recorded at different positions in the table below. Use the data in the table to determine the amoun
natta225 [31]

Answer:

36.55 J

Explanation:

PE = Potential energy

KE = Kinetic energy

TE = Total energy

The following data were obtained from the question:

Position >> PE >>>>> KE >>>>>> TE

1 >>>>>>>> 72.26 >> 27.74 >>>> 100

2 >>>>>>>> 63.45 >> x >>>>>>>> 100

3 >>>>>>>> 58.09 >> 41.91 >>>>> 100

The kinetic energy of the pendulum at position 2 can be obtained as follow:

From the table above, at position 2,

Potential energy (PE) = 63.45 J

Kinetic energy (KE) = unknown = x

Total energy (TE) = 100 J

TE = PE + KE

100 = 63.45 + x

Collect like terms

100 – 63.45 = x

x = 36.55 J

Thus, the kinetic energy of the pendulum at position 2 is 36.55 J.

7 0
2 years ago
in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead the empirical formula of the lead oxide is?​
Romashka-Z-Leto [24]

Answer:

Pb3O4

Explanation:

According to this question, 3.425g of lead oxide was reduced to form 3.105g of lead in an experiment. Since lead oxide contains both lead (Pb) and oxygen (O) element,

Mass of lead oxide = 3.425g

Mass of lead = 3.105g

Mass of oxygen = (3.425g - 3.105g) = 0.320g

Next, we convert each mass value to mole by dividing by respective molar mass

Pb = 3.105g ÷ 207.2 = 0.0149mol

O = 0.320g ÷ 16 = 0.02mol

Next, we divide each mole value by the smallest (0.0149)

Pb = 0.0149mol ÷ 0.0149mol = 1

O = 0.02mol ÷ 0.0149mol = 1.342

Multiply each ratio value by 3 to get:

Pb = 1 × 3 = 3

O = 1.342 × 3 = 4.026

The whole number ratio, approximately, of Pb and O is 3:4, hence, their empirical formula is Pb3O4.

4 0
3 years ago
1.Bubbling or fizzing is an indicator of
hodyreva [135]
D is the answer since it is changing the element.
6 0
3 years ago
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