1.Mr. Bowen’s test is normally distributed with a mean of 75 and a standard deviation of 3 points.

Mathematics

1 answer:

lianna [129]3 years ago

7 0

Answer:

2.28%

Step-by-step explanation:

Mr. bowens test is normally distributed with a mean (μ) of 75 and a standard deviation (σ) of 3 points.

The z score is used in probability to show how many standard deviation is a raw score below or above the mean. The formula for the z score (z) is given by:

$z=\frac{x-\mu}{\sigma}$

For a raw score (x) of 81 points, the z score can be calculated by:

$z=\frac{x-\mu}{\sigma}=\frac{81-75}{3}=2$

Therefore from the normal probability distribution table, the probability that a randomly selected score is greater than 81 can be given as:

P(x > 81) = P(z > 2) = 1 - P(z < 2) = 1 - 0.9772 = 0.0228 = 2.28%

You might be interested in

Two Questions please help and explain

ozzi

Question #2
Erica will have to work for 14 hours in order to buy her sneakers.
How to solve:
You subtract $31 from $150 which equals to $119
You multiply 8.50 (which is the amount of money she gets paid every hour) by the answers they gave you.
8.50 multiplied by 14 is 199
Erica had to work 14 hours to make $199

Your answer is D) 14

4 0

3 years ago

Read 2 more answers

Help me asap how to understand Measuring Angles

Whitepunk [10]

this depends. you can measure angles in real life with a protractor or just use your eye. let us start with the protractor. place the midpoint of a protractor on the vertex of the angle and make sure it lines up to 0. on the other side read the degrees (make sure everything aligns). without a protractor you can use the Sine Formula and measure the lines.

4 0

3 years ago

Read 2 more answers

Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe

icang [17]

Answer:

(-1, -32) absolute minimum
(0, 0) relative maximum
(2, -32) absolute minimum
(+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

h(-1) = 8(-1)²(-1-3) = -32

h(0) = 8(0)(0-3) = 0

h(2) = 8(2²)(2 -3) = -32

h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

(-1, -32) absolute minimum
(0, 0) relative maximum
(2, -32) absolute minimum
(+∞, +∞) absolute maximum

_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.