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2 years ago

Can someone help me with theses 17 points and mark

Mathematics

1 answer:

lukranit [14]2 years ago

7 0

Answer:

Use the app photomath, it almost always finds answers for worksheets.

Step-by-step explanation:

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Farmer Brown has 42 animals, which are cows and chickens. They have a total of 120 legs. Write a system of equations, show your

SCORPION-xisa [38]

Answer:

The system of equations is:

x + y = 42

4x + 2y = 120

And there are 24 chickens.

Step-by-step explanation:

We know that the total number of cows (x) plus the total number of chickens (y) is 42, because Farmer Brown has 42 animals.

We also know that cows (x) have 4 legs and so 4 times the number of cows is the number of cow legs. And chickens (y) have 2 legs, so the number of chickens times two represents the total chicken legs. The sum of 4x + 2y is 120 because there are 120 legs in total.

To solve the system of equations, first solve each equation for y.

In the first equation:

x + y = 42

Subtract x from both sides to isolate y.

y = 42 - x

Second equation:

4x + 2y = 120

Subtract 4x from both sides

2y = 120 - 4x

Divide both sides by 2

y = 60 - 2x

Now that the y's are isolated in both equation, you can put them into 1 equation. Where y = y:

y = 42 - x

y = 60 - 2x

42 - x = 60 - 2x

Add 2x to both sides

42 + x = 60

Subtract 42 from both sides

x = 18

Since x is the number of cows, we know that Farmer Brown has 18 cows.

Now we can substitute the x value into one of the equations:

y = 42 - x

y = 42 - (18)

y = 24

The number of chickens is represented by y, so there are 24 chickens.

3 0

2 years ago

In circle M, diameters JL and HK each measure 16

creativ13 [48]

Answer:

3.5 cm

Step-by-step explanation:

In the picture attached, circle M is shown.

From the picture, minor arc JH measures 25°.

The length of the circle is π*Diameter = π*16 = 50.26 cm. This length is proportional to 360°. To find the length of minor arc JH, we have to use the next proportion:

50.26 cm / x cm = 360° / 25°

x = 50.26*25/360

x = 3.5 cm