The formula for distance problems is: distance = rate × time or d = r × t
Things to watch out for:
Make sure that you change the units when necessary. For example, if the rate is given in miles per hour and the time is given in minutes then change the units appropriately.
It would be helpful to use a table to organize the information for distance problems. A table helps you to think about one number at a time instead being confused by the question.
The following diagrams give the steps to solve Distance-Rate-Time Problems. Scroll down the page for examples and solutions. We will show you how to solve distance problems by the following examples:
Traveling At Different Rates
Traveling In Different Directions
Given Total Time
Wind and Current Problems.
<span><span>Solve <span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120 </span></span>><span><span> 0</span>. </span></span><span>First, I factor to find the zeroes:<span><span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120</span><span>= (x + 5)(x + 3)(x + 1)(x – 2)(x – 4) = 0</span></span><span>...so </span><span>x = –5, –3, –1, 2,</span><span> and </span>4<span> are the zeroes of this polynomial. (Review how to </span>solve polynomials, if you're not sure how to get this solution.)<span>To solve by the Test-Point Method, I would pick a sample point in each interval, the intervals being </span>(negative infinity, –5)<span>, </span>(–5, –3)<span>, </span>(–3, –1)<span>, </span>(–1, 2)<span>, </span>(2, 4)<span>, and </span>(4, positive infinity). As you can see, if your polynomial or rational function has many factors, the Test-Point Method can become quite time-consuming.<span>To solve by the Factor Method, I would solve each factor for its positivity: </span><span>x + 5 > 0</span><span> for </span><span>x > –5</span>;<span>x + 3 > 0</span><span> for </span><span>x > –3</span><span>; </span><span>x + 1 > 0</span><span> for </span><span>x > –1</span><span>; </span><span>x – 2 > 0</span><span> for </span><span>x > 2</span><span>; and </span><span>x – 4 > 0</span><span> for </span><span>x > 4</span>. Then I draw the grid:...and fill it in:...and solve:<span>Then the solution (remembering to include the endpoints, because this is an "or equal to" inequality) is the set of </span>x-values in the intervals<span> [–5, –3]<span>, </span>[–1, 2]<span>, and </span>[4, positive infinity]</span>. </span>
As you can see, if your polynomial or rational function has many factors, the Factor Method can be much faster.
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Answer:
The answer is below
Step-by-step explanation:
The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given as:
Given that μ = $72,641 and σ = $30,000.
a) x > $100000
P(x > 100000) = P(z > 0.91) = 1 - 0.8186 = 0.1814
b) n = 5
x > $100000
P(x > 100000) = P(z > 2.04) = 1 - 0.9793 = 0.0207
c) n = 10
x > $100000
P(x > 100000) = P(z > 2.88) = 1 - 0.9980 = 0.002
354 as a percentage is 354%
35.4 as a percentage is 35.4%
Answer:
a = 30
b = 15
c = 3
d = 30
e = 10
f = 20
Step-by-step explanation:
60 deg and a + 30 are alt int <S and congruent
a + 30 = 60
a = 30
a + 30 and a + 2b are corresponding angles and congruent
a + 2b = a + 30
2b = 30
b = 15
a + 2b and 5b - 5c are vertical angles and congruent
5b - 5c = a + 2b
5(15) - 5c = 30 + 2(15)
75 - 5c = 30 + 30
75 - 5c = 60
-5c = -15
c = 3
a + 2b and 10c + d are corresponding angles and congruent
10c + d = a + 2b
10(3) + d = 30 + 2(15)
d + 30 = 60
d = 30
5b - 5c and 2d + 6e are supplementary and add to 180
5b - 5c + 2d + 6e = 180
5(15) - 5(3) + 2(30) + 6e = 180
75 - 15 + 60 + 6e = 180
6e + 120 = 180
6e = 60
e = 10
2d + 6e and 4f + 4e are alt int angles and congruent.
4f + 4e = 2d + 6e
4f + 4(10) + 2(30) + 6(10)
4f + 40 = 60 + 60
4f + 40 = 120
4f = 80
f = 20
