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lions [1.4K]
2 years ago
13

Solve using test intervals |x 1|> or equal to 4

Mathematics
1 answer:
insens350 [35]2 years ago
4 0
<span><span>Solve <span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120 </span></span>><span><span> 0</span>. </span></span><span>First, I factor to find the zeroes:<span><span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120</span><span>= (x + 5)(x + 3)(x + 1)(x – 2)(x – 4) = 0</span></span><span>...so </span><span>x = –5, –3, –1, 2,</span><span> and </span>4<span> are the zeroes of this polynomial. (Review how to </span>solve polynomials, if you're not sure how to get this solution.)<span>To solve by the Test-Point Method, I would pick a sample point in each interval, the intervals being </span>(negative infinity, –5)<span>, </span>(–5, –3)<span>, </span>(–3, –1)<span>, </span>(–1, 2)<span>, </span>(2, 4)<span>, and </span>(4, positive infinity). As you can see, if your polynomial or rational function has many factors, the Test-Point Method can become quite time-consuming.<span>To solve by the Factor Method, I would solve each factor for its positivity: </span><span>x + 5 > 0</span><span> for </span><span>x > –5</span>;<span>x + 3 > 0</span><span> for </span><span>x > –3</span><span>; </span><span>x + 1 > 0</span><span> for </span><span>x > –1</span><span>; </span><span>x – 2 > 0</span><span> for </span><span>x > 2</span><span>; and </span><span>x – 4 > 0</span><span> for </span><span>x > 4</span>. Then I draw the grid:...and fill it in:...and solve:<span>Then the solution (remembering to include the endpoints, because this is an "or equal to" inequality) is the set of </span>x-values in the intervals<span> [–5, –3]<span>, </span>[–1, 2]<span>, and </span>[4, positive infinity]</span>. </span>

As you can see, if your polynomial or rational function has many factors, the Factor Method can be much faster.

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3 years ago
3x+5(2+x)=4x-7 help me out here?
Oksi-84 [34.3K]

Answer:

x = -17/4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Distributive Property

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

3x + 5(2 + x) = 4x - 7

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Distributive Property] Distribute 5:                                                                 3x + 10 + 5x = 4x - 7
  2. [Addition] Combine like terms:                                                                        8x + 10 = 4x - 7
  3. [Subtraction Property of Equality] Subtract 4x on both sides:                      4x + 10 = -7
  4. [Subtraction Property of Equality] Subtract 10 on both sides:                       4x = -17
  5. [Division Property of Equality] Divide 4 on both sides:                                  x = -17/4
6 0
2 years ago
Read 2 more answers
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