Answer:
yes because the slope is equal. so these two lines are parallel.
Answer:
Part A:
The probability that all of the balls selected are white:

Part B:
The conditional probability that the die landed on 3 if all the balls selected are white:

Step-by-step explanation:
A is the event all balls are white.
D_i is the dice outcome.
Sine the die is fair:
for i∈{1,2,3,4,5,6}
In case of 10 black and 5 white balls:






Part A:
The probability that all of the balls selected are white:


Part B:
The conditional probability that the die landed on 3 if all the balls selected are white:
We have to find 
The data required is calculated above:

Answer:
y=x216–6x16+4116
Step-by-step explanation:
plato :)
Answer:
P(x=25)=P(z=2)=0.9972 or 99.72%
Step-by-step explanation:
Mean = 18 pounds
Standard Deviation = 3.5 pounds
x= 25
We need to find P(x=25)
First, we need to find z-score using formula: 
Finding z-score when x=25

So, we need to find P(z=2)=P(x=25)
Looking at z-score table we can find P(z=2)
P(z=2)=0.9972 or 99.72%
So, P(z=2)=0.9972 or 99.72%
Answer:
90
Step-by-step explanation:
each dot = 45 bc 540 / how many dots there are which is 12 = 45 then there are 2 dots worth of 45 making it 90
math
540/12=45
45 x 2 = 90