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klasskru [66]
3 years ago
5

WILL CHOOSE BRAINLIEST! Find the surface area of a box with a length of 5 inches, a width of 6 inches and a height of 8 inches ?

I NEED IT QUICK
Mathematics
2 answers:
alex41 [277]3 years ago
7 0

<u>Given</u><u>:</u>

  • Length,l = 5 inches

  • Breadth, b or width = 6 inches

  • Height, h = 8 inches

<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u> </u><u>:</u>

Find the surface area of box ( cuboid ) ?

<u>Formula used </u><u>:</u>

Surface area of cuboid = 2 ( lb + bh + hl )

<u>Solution</u><u>:</u>

We know that,

Surface area of cuboid = 2 ( lb + bh + hl )

★Substituting the values in the above formula,we get

Surface area = 2 ( 5 × 6 + 6 × 8 + 8 × 5 )

= 2 ( 30 + 48 + 40 )

= 2 ( 78 + 40 )

= 2 × 118

= 236 inches³

krek1111 [17]3 years ago
6 0

Surface Area = 2×(5×6 + 5×8 + 6×8) = 236 meters²

Hope this helps! Stay safe, have a good day :D

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A parking lot holds 42 cars. There are 26 cars in the lot already. Which inequality can be solved to show all the numbers of car
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In isosceles right triangle ABC, point is on hypotenuse \overline{BC} such that \overline{AD} is an altitude of \triangle ABC an
Dmitriy789 [7]

Answer:

Area of triangle is 25.

Step-by-step explanation:

We have been given an isosceles right triangle

Isosceles triangle is the triangle having two sides equal.

Figure is shown in attachment

By Pythagoras theorem

BC^2=AC^2+AB^2

AD is altitude which divides the triangle into two parts

DC=5 implies BC =10 since D equally divides BC

Let AC=a implies AB=a being Isosceles

On substituting the values in the Pythagoras theorem:

10^2=a^2+a^2

100=2a^2

\Rightarrow a^2=50

\Rightarrow a=\pm5\sqrt{2}

WE can find area of right triangle by considering height AB and AD

Area of triangle ABC is:

\frac{1}{2}\cdot BC\cdot AD     (1)

\Rightarrow \frac{1}{2}\cdot 10\cdot AD

And other method of area of triangle is:

\frac{1}{2}\cdot AB\cdot BC       (2)

Equating (1) and (2) we get:

\frac{1}{2}\cdot 10\cdot AD=\frac{1}{2}\cdot a\cdot a

\Rightarrow AD=\frac{a^2}{10}

\Rightarrow AD=\frac{50}{10}=5

Using area of triangle is: \frac{1}{2}\cdot BC\cdot AD

Now, the area of triangle ABC=\frac{1}{2}\cdot 5\cdot 10

\Rightarrow 25



4 0
3 years ago
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