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Fed [463]
3 years ago
15

A sum of money is divided in the ratio 2 : 3 : 7 .Given the largest share is $112,calculate the smallest share.

Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0

Answer:

$32

Step-by-step explanation:

A sum of money is divided in the ratio 2:3:7.

Let the share of each individual be represented by 2x,3x,7x respectively.

The largest share (7x) is given as $112.

\[7x = 112\]

\[=>x = \frac{112}{7}\]

\[=>x = 16\]

So the respective shares are \[2\times16,3\times16,7\times16\]

In other words, the shares are 32,48,112.

So the smallest share is $32

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15 Pts + Brainliest for the best answer
34kurt

If T is the midpoint of SU, then ST ≅ TU.

Therefore we have the equation:

6x = 2x + 32       <em>subtract 2x from both sides</em>

4x = 32       <em>divide both sides by 4</em>

x = 8

ST = 6x → ST = 6(8) = 48

TU = ST, therefore ST = 48

SU = ST + TU = 2ST, therefore SU = 2(48) = 96

<h3>Answer: ST = 48, TU = 48, SU = 96</h3>
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

1.

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3 years ago
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Answer:

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Step-by-step explanation:

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