The anser is 50 becasue if u had an mini 1 above 1 that would mean u had to multiply it 5x10 2 time fro example 5x20 = 100
Answer: P(22 ≤ x ≤ 29) = 0.703
Step-by-step explanation:
Since the machine's output is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = output of the machine in ounces per cup.
µ = mean output
σ = standard deviation
From the information given,
µ = 27
σ = 3
The probability of filling a cup between 22 and 29 ounces is expressed as
P(22 ≤ x ≤ 29)
For x = 22,
z = (22 - 27)/3 = - 1.67
Looking at the normal distribution table, the probability corresponding to the z score is 0.047
For x = 29,
z = (29 - 27)/3 = 0.67
Looking at the normal distribution table, the probability corresponding to the z score is 0.75
Therefore,
P(22 ≤ x ≤ 29) = 0.75 - 0.047 = 0.703
Vă rugăm să găsiți imaginea întrebării atașate mai jos:
Răspuns:
A este proporțională
B este proporțională
C nu este proporțional
D este proporțional
E nu este proporțională
F este proporțional
Explicație pas cu pas:
Pentru a determina proporționalitatea:
Obținem constanta proporționalității
Pentru valorile din tabelul 1;
Luând primul punct:
x = 1; y = 5
1 α 5
1 = 5k
k = 1/5
Test:
y = 15
x = k * y
x = 1/5 * 15; x = 3
Prin urmare; (a) este proporțională
B.)
x = 2; y = 6
2 α 6
2 = 6k
k = 2/6
k = 1/3
Test:
y = 15
x = k * y
x = 1/3 * 15; x = 5
Prin urmare; (b) este proporțională
C.)
x = 2; y = 6
7 α 3,5
7 = 3,5k
k = 7 / 3,5
k = 2
Test:
y = 5
x = 2 * 3.5
x = 7
Prin urmare; (c) nu este proporțională
x = 0,5; y = 1
0,5 α 1
0,5 = k
Test:
y = 4
x = k * y
x = 0,5 * 4; x = 2
Prin urmare; (d) este proporțională
x = 0,2; y = 2
0,2 α 2
0,2 = 2k
k = 0,2 / 2
k = 0,1
Test:
y = 4,5
x = 0,1 * 4,5
x = 0,45
Prin urmare; (e) nu este proporțională
x = 1; y = 12
1 α 12
1 = 12k
k = 1/12
Test:
y = 84
x = 1/12 * 84
x = 7
Prin urmare; (f) este proporțională
Answer:
3/2
Step-by-step explanation:
ugygv
<h3>Refer to the diagram below</h3>
- Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
- Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
- Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
- Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
- Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.
Refer to the diagram below for examples of what I mean.