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bearhunter [10]
3 years ago
6

Please somebody help me with this please help ASAP​

Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

Step-by-step explanation:

I don't know what your teacher wants to hear here.

can you use and construct certain angles (particularly 90 degrees), can you use compasses ?

for me the best way would be to draw one side as given. then use compasses and draw a half-circle from each end point of the line above the line. both circles have the radius = the given diameter.

then draw the next 2 sides of the square up from the end points of the first line towards the half-circle that was drawn from the other point, so that the end point is exactly on the circle bow. and then connect the engaging endpoints of these 2 sides.

similar for the rectangle.

the only difference is that now for the two sides (which we don't know the length) we need to go up exactly 90 degrees until the lines hit the half-circles.

You might be interested in
What's 5x10 exponent 1
strojnjashka [21]
The anser is 50 becasue if u had an mini 1 above 1 that would mean u had to multiply it 5x10 2 time fro example 5x20 = 100
6 0
3 years ago
Read 2 more answers
A soft drink machine outputs a mean of 27 ounces per cup. The machine's output is normally distributed with a standard deviation
postnew [5]

Answer: P(22 ≤ x ≤ 29) = 0.703

Step-by-step explanation:

Since the machine's output is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = output of the machine in ounces per cup.

µ = mean output

σ = standard deviation

From the information given,

µ = 27

σ = 3

The probability of filling a cup between 22 and 29 ounces is expressed as

P(22 ≤ x ≤ 29)

For x = 22,

z = (22 - 27)/3 = - 1.67

Looking at the normal distribution table, the probability corresponding to the z score is 0.047

For x = 29,

z = (29 - 27)/3 = 0.67

Looking at the normal distribution table, the probability corresponding to the z score is 0.75

Therefore,

P(22 ≤ x ≤ 29) = 0.75 - 0.047 = 0.703

6 0
3 years ago
Stabiliti daca marimile ale caror valori sunt trecute in tabelele urmatoare sunt direct proportionale.
kvv77 [185]

Vă rugăm să găsiți imaginea întrebării atașate mai jos:

Răspuns:

A este proporțională

B este proporțională

C nu este proporțional

D este proporțional

E nu este proporțională

F este proporțional

Explicație pas cu pas:

Pentru a determina proporționalitatea:

Obținem constanta proporționalității

Pentru valorile din tabelul 1;

Luând primul punct:

x = 1; y = 5

1 α 5

1 = 5k

k = 1/5

Test:

y = 15

x = k * y

x = 1/5 * 15; x = 3

Prin urmare; (a) este proporțională

B.)

x = 2; y = 6

2 α 6

2 = 6k

k = 2/6

k = 1/3

Test:

y = 15

x = k * y

x = 1/3 * 15; x = 5

Prin urmare; (b) este proporțională

C.)

x = 2; y = 6

7 α 3,5

7 = 3,5k

k = 7 / 3,5

k = 2

Test:

y = 5

x = 2 * 3.5

x = 7

Prin urmare; (c) nu este proporțională

x = 0,5; y = 1

0,5 α 1

0,5 = k

Test:

y = 4

x = k * y

x = 0,5 * 4; x = 2

Prin urmare; (d) este proporțională

x = 0,2; y = 2

0,2 α 2

0,2 = 2k

k = 0,2 / 2

k = 0,1

Test:

y = 4,5

x = 0,1 * 4,5

x = 0,45

Prin urmare; (e) nu este proporțională

x = 1; y = 12

1 α 12

1 = 12k

k = 1/12

Test:

y = 84

x = 1/12 * 84

x = 7

Prin urmare; (f) este proporțională

7 0
2 years ago
5 and 4 sevenths times negative 2 and 2 fifths
Dimas [21]

Answer:

3/2

Step-by-step explanation:

ugygv

6 0
3 years ago
WILL MARK BRAINLIEST
dsp73
<h3>Refer to the diagram below</h3>
  1. Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
  2. Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
  3. Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
  4. Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
  5. Pull the two circles completely apart. Make sure they don't touch at all. This will allow us to have four different common tangents. Two of those tangents are internal, while the others are external. An internal tangent cuts through the line that directly connects the centers of the circles.

Refer to the diagram below for examples of what I mean.

5 0
3 years ago
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