All categories

3 years ago

A function of the form f(x) ott is modified so that the b value remains the same but the a value is increased by 2. How do

Mathematics

2 answers:

Digiron [165]3 years ago

6 0

Answer:

Step-by-step explanation:

amm18123 years ago

3 0

Answer:

The domain and range of the function will be same after the modification.

Step-by-step explanation:

Domain and Range of the function f(x) is the set of real numbers

Now, the value of the given function f(x) is modified such that the value of b remains same but the value of a is increased by 2

⇒ The domain and range of the modified function is also the set of all real numbers.

Therefore, The domain and range of the function will be same after the modification.

You might be interested in

Give domain from least to greatest points.- (2,1) (3,4) (5,6) (7,5) (9,3)

andre [41]

Answer:

potanginaaaa you ahahahaha plss

Step-by-step explanation:

pa brainliest po baby bago Po Ako dito

7 0

3 years ago

Please help I am begging !!!!!25 points!!!!! Brainlest !!!!!! Please help me I really need it the questions are on the bottom th

tangare [24]

Answer:

A the sybol is facing the wrong way so it means greater than or equal not less than or equal to

B the gross value is accuratly represented and the symbol is facing the correct way

I think

6 0

3 years ago

CAN SOMEONE PLZZ HELP ME THE LAST QUESTION PLZZZZZ?????

MissTica

first is proportional. y is 1 and 1/4 times x

second is not proportional.

reason? divided any y value by its corresponding x value and you'll keep getting 1.25, or 1 and 1/4. and the second one is not proportional because dividing the y values by their corresponding x value will give different answers.

maybe im wrong maybe im right you choose to trust me or not.

5 0

3 years ago

Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0

choli [55]

Hello,
center is (4,-6)
radius=4
since
$x^2-8x+y^2+12y+36=0\\

x^2-2*4x+16-16+y^2+2*6y+36=0\\

(x-4)^2+(y+6)^2=4^2

$

3 0

3 years ago

Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).

kirill115 [55]

Answer:

The Correct option is Last one $y=-4x-4$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

Step-by-step explanation:

Given:

$y=-4x-3$

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

$y=-4x-3$ ..........Given

Comparing with Slope-Intercept form,

$y=mx+c$

Where m =slope

We get

$Slope = m = -4$

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the points and so we will get the required equation of the line,

$(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

8 0

3 years ago