<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
Answer:
113.04 cm
Step-by-step explanation:
First, simplify. Combine like terms
10x - 3x = 7x
7x + 1 = x + 4
Isolate the x. Subtract x from both sides, and 1 from both sides
7x (-x) + 1 (-1) = x (-x) + 4 (-1)
7x - x = 4 - 1
Simplify
6x = 3
Isolate the x. Divide 6 from both sides
6x/6 = 3/6
x = 1/2
1/2, or 0.5 is your answer for x.
hope this helps