Raise 49<span> to the </span>power<span> of </span>2<span> to get </span><span>2401.
</span><span><span>7^3</span>x+4=2401x+1
</span>Raise 7<span> to the </span>power<span> of </span>3<span> to get </span><span>343.
</span><span>343x+4=2401x+1
</span>Since <span>2401x</span><span> contains the </span>variable<span> to solve for, move it to the left-hand side of the </span>equation<span> by subtracting </span><span>2401x</span><span> from both sides.
</span><span>343x+4−2401x=1
</span>Add <span>343x</span><span> and </span><span>−2401x</span><span> to get </span><span><span>−2058x</span>.
</span><span>−2058x+4=1
</span>Since 4<span> does not contain the </span>variable<span> to solve for, move it to the right-hand side of the </span>equation<span> by subtracting </span>4<span> from both sides.
</span><span>−2058x=−4+1
</span>Add <span>−4</span><span> and </span>1<span> to get </span><span><span>−3</span>.
</span><span>−2058x=−3
</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span><span>−2058</span>.
</span><span>x=<span>1/686</span></span>
Answer:
Domain: All real numbers greater than or equal to 0 and less than or equal to 50
Range: All real numbers greater than or equal to 0 and less than or equal to 100
Step-by-step explanation
The workout is at 100% at 50 mins. Anything less would be under these two numbers. Since the percentage of workout is on the y-axis, anything between zero and 100 can be possible. The time is on the x-axis, so anything 0 to 50 can be possible.
Equation of a line:

m = gradient: The difference between two y points and two x points.

c = y-intercept: Where the line crosses the y-axis (x=0)
You have:

so you are missing the m and the c.
To calculate m find two y coordinates -you have (12,
<u>7</u>) and (0, <u>
1</u>)- and subtract them. Then divide this by the subtracted values of the x coordinates -you have (<u>
12</u>, 7) and (<u>
0</u>, 1)- This gives:



To calculate the c, you just see where the line crosses the y-axis. Because you have the point (0, 1), you know that when x=0, y=1. Because x=0 is on the y-axis, you can tell that the line passes through y=1. This makes your c = 1:

When you plug these values into the equation you get your answer:
This is how you do it.
y = a(x - 3)(x - 8)
<span>-2 = a(-1 - 3)(-1 - 8) </span>
<span>-2 = 36a </span>
<span>- 1 / 18 = a </span>
<span>y = ( - 1 / 18)(x^2 - 11x + 24) </span>
<span>y = (- 1 / 18)x^2 + (11 / 18)x - (3 / 2)
</span>
If this doesn't explain it enough, please, ask questions.