In the Position versus Time graph of an object moving in a straight line, what is the change in position in the fourth hour?
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Answer:
the speed of the command module relative to Earth just after the separation = 4943.2 Km/hr
Explanation:
Given:
speed of space vehicle =5000 km/hr
rocket motor speed = 71 km/hr relative to the command module
mass of module = m
mass of motor = 4m
By conservation of linear momentum
Pi = Pf
Pi= initial momentum
Pf= final momentum
Since, the motion is only in single direction
Where M is the mass of the space vehicle which equals the sum of motor's mass and the command's mass, Vi its initial velocity, V_mE is velocity of motor relative to Earth, and V_cE is its velocity of the command relative to Earth.
The velocity of motor relative to Earth equals the velocity of motor relative to command plus the velocity of command relative to Earth.
V_mE = V_mc+V_cE
Where V_mc is the velocity of motor relative to command this yields
substituting the values we get
= 4943.2 Km/hr
the speed of the command module relative to Earth just after the separation = 4943.2 Km/hr
To solve this problem it is necessary to apply the concepts related to the kinematic equations of angular motion.
By definition, acceleration can be expressed as the change in angular velocity squared over a given period of distance traveled.
where,
Angular velocity
Angular displacement.
In turn, as a function of time, we can represent it as,
For our case we have to,
PART A) In the case of angular acceleration we have to,
PART B) Through the definition of angular acceleration as a function of time we can calculate it,