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3 years ago

8

When light travels through a small hole, it appears to be an observer that the light spreads out, blurring the outline of the ho

le. Does this observation support the theory of light as a wave, or light being made of particles? Explain.

1 answer:

3241004551 [841]3 years ago

7 0

Answer:

support lights as a wave

Explanation:

In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.

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The use of nuclear reactors to generate electricity is?

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The difference is that nuclear plants do not burn anything. Instead, they use uranium fuel, consisting of solid ceramic pellets, to produce electricity through a process called fission<span>. Nuclear power plants obtain the heat needed to produce steam through a physical process.

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A flat plate maintained at a temperature of 80°C experiences a flow of atmospheric air at 0°C. If the temperature gradient at th

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Answer:

h =12.9 w/m2 k

Explanation:

we know that thermal conductivity of air K at 0 degree celcius = 0.024 w/mk

T_S = 80 Degree celcius

temperature gradient = -43 degree C/mm = - 43*1000 / m $\frac{dT}{dx} = - 43*1000 / m$

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3 years ago

While performing an experiment involving a reaction between two chemicals, the scientist observes that the reaction container ha

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When an object is becomes warm its an example of exothermic reaction.

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An airplane flies 1,592 miles east from Phoenix Arizona, to Atlanta,Georgia,in 3.68 hours. What is the average velocity of the a

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The average velocity would be 217 m/s.

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4 years ago

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The specific heat of soil is 0.20 kcal/kg*C and the specific heat of water is 1.00 kcal/kg*C. This means that if 1 kg of soil an

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Answer: The soil will be $4\°C$ warmer than the water.

Explanation:

The heat (thermal energy) absorbed can be found using the following equation:

$Q=m.C.\Delta T$

Where:

$Q$ is the heat

$m$ is the mass of the element

$C$ is the specific heat capacity of the material.

$\Delta T$ is the variation in temperature

<u>In the case of soil we have:</u>

$Q_{soil}=m_{soil}.C_{soil}.\Delta T_{soil}$ (1)

Where:

$Q_{soil}=1 kcal$

$m_{soil}=1 kg$

$C_{soil}=0.2 kcal/kg \°C$

$\Delta T_{soil}$

<u>In the case of water we have:</u>

$Q_{water}=m_{water}.C_{water}.\Delta T_{water}$ (2)

Where:

$Q_{water}=1 kcal$

$m_{water}=1 kg$

$C_{water}=1 kcal/kg \°C$

$\Delta T_{water}$

Isolating $\Delta T$ from both equations:

$\Delta T_{soil}=\frac{Q_{soil}}{m_{soil}.C_{soil}}$ (3)

$\Delta T_{soil}=\frac{1 kcal}{1 kg(0.2 kcal/kg \°C)}$

$\Delta T_{soil}=5\°C$ (4)

$\Delta T_{water}=\frac{Q_{water}}{m_{water}.C_{water}}$ (5)

$\Delta T_{water}=\frac{1 kcal}{1 kg(1 kcal/kg \°C)}$

$\Delta T_{water}=1\°C$ (6)

Comparing (4) and (6) we can find the soil will be $4\°C$ warmer than the water.

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4 years ago