1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gala2k [10]
3 years ago
7

What is the least possible degree of a polynomial that has roots -5, 1+4i, and -4i

Mathematics
1 answer:
N76 [4]3 years ago
3 0
If complex coefficients are allowed, the answer is 3.

If the polynomial must have real coefficients, then each complex root comes as a pair of complex conjugate roots.

Root -5 is real, so that is 1 root, and degree 1.

Root 1 + 4i is complex, so it must come with its complex conjugate, 1 - 4i. This adds 2 roots to the polynomial, and now we're up to degree 3.

Root -4i is also complex. It also must come with its complex conjugate, 4i. That adds two more roots, and the degree is 5.

Answer: The least possible degree is 5 with real coefficients.
You might be interested in
Identify the percent of change as an increase or decrease. Then find the percent of change, rounding to the nearest tenth of a p
kap26 [50]

Answer:

-60% decrease

Step-by-step explanation:

60 is the old value and 24 is the new value.

percent change = \frac{new - old}{|old|} x 100%

so for this problem, you can substitute the values given in the formula:

percent change = \frac{60-24}{|60|} x 100% = \frac{-36}{60} x 100% =

-60% (decrease)  

3 0
3 years ago
A math class has 3 girls and 7 boys in the 7th grade and 5 girls and 5 boys in the 8th grade the teacher randomly selects a seve
Minchanka [31]
In the 7th and 8th grade combined, there 3+5 girls = 8 girls, and 7+5 boys = 12 boys. If there are only boys and girls, then there are 12+8=20 students in all. 

The fraction of girls out of the total is P = 8/20 = 2/5.
8 0
3 years ago
Napstablook makes some very amazing spooky tunes
yan [13]

Answer:

? is that the question? is there a link for it or something?

Step-by-step explanation:

8 0
3 years ago
The measure of angle B is 65.8°. find the measure of the complement and supplement of angle B.​
viktelen [127]

Answer:

The fourth choice

24.2° and 114.2°

Step-by-step explanation:

Complementary angles add up to 90°

Supplementary angles add up to 180°

*a trick to remember this is to know that C is before S in the alphabet, and 90 is before 180, so Complementary is 90 and Supplementary is 180

Step 1:  Find the complementary angle

  Take 90° and subtract the give angle to find the angle you would need...

       90° - 65.8° = 24.2°

Step 1:  Find the supplementary angle

  Take 180° and subtract the give angle to find the angle you would need...

       180° - 65.8° =  114.2°

3 0
3 years ago
A circle has an area of p square feet and a circumference of q feet. If p=2.5q, what is the radius of the circle?
Zinaida [17]
A=.5*r^2*theta
a=p
2.5q=2pi(r)
2pi(r)=.5(r^2)(2pi)
1=.5r
2=r
3 0
3 years ago
Other questions:
  • The entire graph of the function h is shown below write the domain and range of h using interval notation.
    7·1 answer
  • Scoring a hole-in-one is the greatest shot a golfer can make. Once 5 professional golfers each made holes-in-one on the 7th hole
    5·1 answer
  • When a jug is half-filled with marbles, it weighs 2.6 kg. If the jug weighs 4 kg when full, find the weight of the empty jug.
    9·2 answers
  • Find the equation of the line
    15·2 answers
  • the ratio of weight to mass is constant.which statement describes the ratio of weight to mass and the value of x in the table
    15·1 answer
  • 3 -² =<br><br> Evaluate each expression.
    9·2 answers
  • Many inches in 2 feet i nches =2 feet
    10·2 answers
  • Find the inverse variation equation that relates x and y.
    7·1 answer
  • BRAINLIEST FOR THE CORRECT AWNSER!! PLEASE PUT THE LETTER AWNSER AND EXPLAIN DO NOT LIE THANK YOU The owner of a bike shop sells
    9·1 answer
  • Please help this is due at 8 i'll mark you brainlist
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!