Answer:
C-D
Explanation:
As you can see from the graph, the distance from A to B was from 0 m to 6 m in a duration of 3 seconds.
Divide 6 meters by 3 seconds to find the speed:
6 ÷ 3 = 2 m/s
B-C is not moving due to a straight line as said in the graph, so speed is
0 m/s.
There is also C-D since the car traveled from a distance of 9 meters
(6 -(-3) = 9) in 3 seconds too. (NOTE: The graph line going down does not mean it is slowing down, but rather going to a certain distance like going backwards)
Divide 9 meters by 3 seconds to get the speed:
9 ÷ 3 = 3 m/s
Between A-B, B-C, and C-D, C-D has the fastest speed recorded with 3 m/s.
A-D does not count here as the line has no connection between point A and point D.
Cheers!
Answer:
beam of light converges to a point A. A lens is placed in the path of the convergent beam 12 cm from P.
To find the point at which the beam converge if the lens is (a) a convex lens of focal length 20 cm, (b) a concave lens of focal length 16 cm
Solution:
As per the given criteria,
the the object is virtual and the image is real (as the lens is placed in the path of the convergent beam)
(a) lens is a convex lens with
focal length, f=20cm
object distance, u=12cm
applying the lens formula, we get
f
1
=
v
1
−
u
1
⟹
v
1
=
f
1
+
u
1
⟹
v
1
=
20
1
+
12
1
⟹
v
1
=
60
3+5
⟹v=7.5cm
Hence the image formed is real, at 7.5cm from the lens on its right side.
(b) lens is a concave lens with
focal length, f=−16cm
object distance, 12cm
applying the lens formula, we get
f
1
=
v
1
−
u
1
⟹
v
1
=
f
1
+
u
1
⟹
v
1
=
−16
1
+
12
1
⟹
v
1
=
48
−3+4
⟹v=48m
Hence the image formed is real, at 48 cm from the lens on the right side.
We add the values on each of the riders:
300 + 20 + 8
= 328 grams
