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AysviL [449]
3 years ago
11

Find the potential energy associated with a 79-kg hiker atop New Hampshire's Mount Washington, 1900 m above sea level. Take the

zero of potential energy at sea level.
Physics
1 answer:
Agata [3.3K]3 years ago
7 0

Answer:

P = 1470980 J

Explanation:

We have,

Mass of the hiker is 79 kg

It is required to find the potential energy associated with a 79-kg hiker atop New Hampshire's Mount Washington, 1900 m above sea level.

It is given by :

P=mgh\\\\P=79\times 9.8\times 1900\\\\P=1470980\ J

So, the potential energy of 1470980 J is associated with a hiker.

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6 0
4 years ago
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Millions of children are treated each year for sports-related injuries.
miv72 [106K]

Answer:

True

Explanation:

As per a survey conducted in the United States, it has been highlighted that among 30 million children participating in any sports, there are 3.5 million children who face injuries. It is because of these injuries that the children have to take some leave or absence from the sports. Also, the statistics discloses the fact that among all the injuries faced by the humans, one third of them are related to the childhood sports activities. Sprains and strains are among the most common of the injuries.

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3 years ago
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A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and Ez = (4.3
Ivan

Answer:

B_{m}=1.4333*10^{-8}T

Explanation:

Given data

Ex = Ey = 0

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

To find

The amplitude of the magnetic field component

Solution

The electric field is given by:

Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

Where Em=4.3 V/m

The magnitude of magnetic field is given by:

B_{m}=\frac{E_{m}}{c}

Where Em is amplitude of electric field and c is speed of light.

Substitute the given values

So

B_{m}=\frac{4.3V/m}{3.0*10^{8}m/s }\\B_{m}=1.4333*10^{-8}T

7 0
3 years ago
What is the mean of the data set 3cm, 7cm, 7cm, 7cm, 9cm, 11cm, 12cm
zzz [600]
The correct answer for the mean would be 8

I hope that this helps !
6 0
4 years ago
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Two charged particles attract each other with a force of magnitude F acting on each. If the charge of one is doubled and the dis
irakobra [83]

Answer:

F/2

Explanation:

In the first case, the two charges are Q1 and Q2 and the distance between them is r. K is the Coulomb's constant

Hence;

F= KQ1Q2/r^2 ------(1)

Where the charge on Q1 is doubled and the distance separating the charges is also doubled;

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F2= F/2

Comparing (1) and (2)

The magnitude of force acting on each of the two particles is;

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