A parallel plate flow chamber is being designed to study the adhesion of leukocytes to endothelium. The channel width is 2cm; th
1 answer:
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Answer:
direction is given as
South of West
Explanation:
Part b)
displacement is given as
now we will have
total displacement is given as
direction is given as
South of West
Answer:
a) El trabajo realizado es de 274,680 J
b) La potencia de la carretilla elevadora es de 4578 Watts.
c) La energía cinética del montacargas es de 3.888. J
d) La energía potencial del montacargas es de 274.680 Joules.
e) La energía mecánica de la carretilla elevadora 278,568. J
Explanation:
a) Los parámetros dados son;
La velocidad de la carretilla elevadora, v = 12 km / h = 10/3 m / s
La masa que debe levantar la carretilla elevadora, m = 700 kg
La altura a la que se levantará la masa, h = 40 m
El trabajo realizado, W = Fuerza, F × Distancia, h
La fuerza, F aplicada = El peso de la carga = Masa, m × Gravedad, g
Donde 'g' es la aceleración debida a la gravedad ≈ 9,81 m / s²
∴ Trabajo realizado, W = 700 kg × 9,81 m / s² × 40 m = 274,680 J
b) El tiempo que se tarda en subir 40 m = 1 minuto = 60 segundos
∴ Potencia = Trabajo / tiempo
Por lo tanto, la potencia del montacargas, P = 274,680 J / (60 s) = 4578 Watts
c) Energía cinética, K.E. = 1/2 · m · v²
La energía cinética de la carretilla elevadora, K.E. se da como sigue;
Carretilla elevadora K.E. = 1/2 × 700 kg × (10/3 m / s) ² = 3.888. J
d) La energía potencial del montacargas a 40 m, P.E. = m · g · h
∴ P.E. = 700 kg × 9,81 m / s² × 40 m = 274,680 Julios
e) La energía mecánica, M.E. = P.E. + K.E.
∴ M.E. = 3.888. J + 274,680 J = 278,568.
J
La energía mecánica de la carretilla elevadora, M.E.= 278,568. J.
Answer:
From certain assumptions that the walking speed is 2 m/s, and the stop time is 0.1 s the acceleration would be -20 m/s
Explanation:
Using the average acceleration formula:
where
and
are the changes in the speed and time respectively.
We have by assuming that the walking speed is 2 m/s and the stop time is 0.1s which is equal to the change in time during the stopping.
, where
are the initial speed and final speed respectively, and
Plugging the previous in the average acceleration formula we get
where the minus sign indicates an acceleration in the opposite direction of the motion (or in other word opposite to the speed's direction).