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Alexeev081 [22]
2 years ago
11

A parallel plate flow chamber is being designed to study the adhesion of leukocytes to endothelium. The channel width is 2cm; th

e viscosity of the tissue culture liquid medium is 0.0087 g/cm-s. Determine channel heights that can be used to generate wall shear stresses (i.e., ) as high as 20 dynes/cm^2 with flow rates less than 2 ml/s.
Physics
1 answer:
DanielleElmas [232]2 years ago
4 0

Answer:

The channel height is 0.0510 cm.

Explanation:

Given that,

Width w= 2 cm

Dynamic viscosity \mu= 0.0087\ g/cm-s

Discharge flow rate Q= 2 ml/s

Shear stress \tau= 20\ dynes/cm²

We need to calculate the channel heights

Using formula of maximum shear stress

\tau=\dfrca{6Q\mu}{H^2w}

H=\sqrt{\dfrac{6Q\mu}{\tau w}}

Put the value into the formula

H=\sqrt{\dfrac{6\times2\times0.0087}{20\times2}}

H=0.0510\ cm

Hence, The channel height is 0.0510 cm.

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Tarzan (who has mass 80.0 kg) is running across the jungle floor with speed 7.00 m/s as
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<u>We are given:</u>

Mass of Tarzan before swinging = 80 kg

Mass of Tarzan when swinging = 80 + 15 = 95 kg

Velocity of Tarzan = 7 m/s

The height of the rock Tarzan's monkey is sitting on = 3 m

__________________________________________________________

<u>Momentum of Tarzan before swinging:</u>

We know that:

Momentum = Mass*Velocity

Momentum = 80 * 7

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__________________________________________________________

<u>Speed of Tarzan after grabbing the bananas:</u>

The momentum of Tarzan will remain the same but his mass will increase

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560 = 95 * v                           [where v is the velocity of Tarzan]

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<u>__________________________________________________________</u>

<h3><u>Finding the Initial and Final KE and PE:</u></h3>

<em>Here, KE = Kinetic Energy and PE = Potential Energy</em>

<u>Initial and Final KE:</u>

We know that KE = 1/2*(mv²)

<u>Initial KE:</u>

Initial KE = 1/2*(mv²)          [where v is the velocity after picking the bananas]

Initial KE = 1/2*(95*5.9²)

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<u>Final KE:</u>

Final KE = 1/2*(mv²)            

<em>[where v is the velocity at the maximum point of the swing]</em>

Since Tarzan will be at rest at the maximum point of the swing, v = 0 m/s

Final KE = 1/2*(95*0²)

Final KE = 0 Joules

<u>Initial and Final PE:</u>

We know that:

PE = mgh                

<em>[where g is the acceleration due to gravity and h is the height]</em>

<u>Initial PE:</u>

Since the height of Tarzan from the ground was 0 m at the beginning of the swing, h = 0

Initial PE = 95*10*0

Initial PE = 0 Joules

<u>Final PE:</u>

Let the maximum height of Tarzan be h m

Final PE = 95*10*h

Final PE = 950(h)

__________________________________________________________

<h3><u>Finding the maximum height Tarzan will reach:</u></h3>

<em>Here, KE = Kinetic Energy and PE = Potential Energy</em>

From the law of conservation of momentum, we know that:

Initial KE + Initial PE = Final KE + Final PE

Replacing the variables:

1653.5 + 0 = 0 + 950h

1653.5 = 950h

h = 1653.5/950         [dividing both sides by 950]

h = 1.74 m

Therefore, the maximum height reached by Tarzan is 1.74 m

but since his monkey is sitting 3 m high, he will NOT be able to reach his monkey

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i hope this helps your answer

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