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2 answers:
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Answer:
Let f_n be the number of rabbit pairs at the beginning of each month. We start with one pair, that is f_1 = 1. After one month the rabbits still do not produce a new pair, which means f_2 = 1. After two months a new born pair appears, that is f_3 = 2, and so on. Let now n 3 be any natural number. We have that f_n is equal to the previous amount of pairs f_n-1 plus the amount of new born pairs. The last amount is f_n-2, since any two month younger pair produced its first baby pair. Finally we have
f_1 = f_2 = 1,f_n = f_n-1 + f_n-2 for any natural n 3.
Answer:
The solutions are (-√6,0) and (√6,0)
(-√5,-1) and (√5,-1)
Step-by-step explanation:
The equations are:
and
We make y the subject in the second equation to get;
We substitute into the first equation to get:
and
The solutions are (-√6,0) and (√6,0)
(-√5,-1) and (√5,-1)