The rate of the reaction will increase by a factor of 9.
Explanation:
Hello,
In this case, considering the given second-order reaction, whose rate law results:
We easily infer that at constant concentration of A but tripling the concentration of B, we are going to obtain the following increasing factor while holding the remaining variables constant:
21.4 g Al * (1 mol / 26.98 g ) * (2 mol Fe / 2 mol Al) = 0.793 mol Fe 91.3 g Fe2O3 * (1 mol / 159.69 g) * (2 mol Fe / 1 mol Fe2O3) = 1.14 mol Fe 0.793 mol Fe * (55.85 g / 1 mol) = 44.3 g Fe produced.