Question

The reaction A + 2B ® products has been found to have the rate law, rate = k[A] [B]2. While holding the concentration of A constant, the concentration of B is increased from x to 3x. Predict by what factor the rate of reaction increases.

Answer 1

Answer:

The rate of the reaction will increase by a factor of 9.

Explanation:

Hello,

In this case, considering the given second-order reaction, whose rate law results:

$r=k[A] [B]^2$

We easily infer that at constant concentration of A but tripling the concentration of B, we are going to obtain the following increasing factor while holding the remaining variables constant:

$Increase\ factor=\frac{r_{final}}{r_{initial}} =\frac{k[A][3*B]^2}{k[A][B]^2} =\frac{3^2}{1} \\Increase\ factor=9$

Best regards.