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7nadin3 [17]
3 years ago
6

Chemical and physical element properties are determined by their valence electrons. How do you describe metals with only one val

ence
electron?
A .highly reactive
B. poor conductors of electricity
C. reactive with other metals
D. likely to gain more electrons
Chemistry
1 answer:
Y_Kistochka [10]3 years ago
7 0

Answer:

B

Explanation:

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The molar solubility of ag2s is 1.26 × 10-16 m in pure water. calculate the ksp for ag2s.
MAXImum [283]
Answer is: Ksp for silver sulfide is 8.00·10⁻⁴⁸.
Reaction of dissociation: Ag₂S(s) → 2Ag⁺(aq) + S²⁻(aq)<span>.
</span>s(Ag₂S) = s(S²⁻) = 1.26·10⁻¹⁶ M.
s(Ag⁺) = 2s(Ag₂S) = 2.52·10⁻¹⁶ M; equilibrium concentration of silver cations.
Ksp = s(Ag⁺)² · s(S²⁻).
Ksp = (2.52·10⁻¹⁶ M)² · 1.26·10⁻¹⁶ M.
Ksp = 6.35·10⁻³² M² · 1.26·10⁻¹⁶ M.
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3 years ago
The process in which the nucleus of an atom splits into two lighter atoms, releasing a large amount of energy, is nuclear .
IgorC [24]

It's nuclear fission

6 0
3 years ago
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What is the volume of a 5M solution with that has 16.5 moles?
kenny6666 [7]
Molarity can be used to calculate the volume of solvent or the amount of solute. The relationship between two solutions with the same amount of moles of solute can be represented by the formula c1V1 = c2V2, where c is concentration and V is volume.
7 0
3 years ago
What is the momentum of a 1,700 kg car travelling in a straight line at 13 m/s?
Anna71 [15]

Answer:

Explanation:

We know that momentum is the product of mass and velocity so here

mass (m) = 1700 kg

velocity (v) = 13 m/s

So now

momentum = m * v

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hope it helps :)

4 0
3 years ago
Using the reaction below: 2 CO2(g) + 2 H2O(l) → C2H4(g) + 3 O2(g) ΔHrxn= +1411.1 kJ What would be the heat of reaction for this
maw [93]

Answer:  d) -705.55 kJ

Explanation:

Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.

2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g) \Delta H=+1411.1kJ

Reversing the reaction, changes the sign of \Delta H

C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)

\Delta H=-1411.1kJ

On multiplying the reaction by \frac{1}{2} , enthalpy gets half:

0.5C_2H_4(g)+1.5O_2(g)\rightarrow CO_2(g)+H_2O(l)\Delta H=\frac{1}{2}\times -1411.1kJ=-705.55kJ/mol

Thus the enthalpy change for the given reaction is -705.55kJ

7 0
3 years ago
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