Answer:
2Zn + 2HCI ➡️ ZnCI2 + H2
LHS of equation
Z = 2
H = 2
Cl = 2
RHS of equation
Zn = 1
Cl =2
H =2
as Zn is not equal in number of atoms on both sides of the equation, the equation does not obey the law of conservation of mass
Explanation:
the law of conservation mass states that the mass of an isolated system cannot be created nor destroyed by any chemical reaction or physical transformation. thus, there must be an equal number of atoms of an element present on both sides of the equation.
The haze is called smog, hope this helps, pls mark brainliest!
The mean kinetic energy per molecule is , where is the Boltzmann constant and T is the absolute temperature.
So at 1000°C, the T = 1273.15 K, kB=1.38 × 10-23, therefore the mean kinetic energy is 2.635 × 10⁻²⁰J.
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What is Kinetic energy ?</u></h3>
The energy an item has as a result of motion is known as kinetic energy.
A force must be applied to an item in order to accelerate it. We must put forth effort in order to apply a force. After the job is finished, energy is transferred to the item, which then moves at a new, constant speed. Kinetic energy is the type of energy that is transmitted and is dependent on the mass and speed attained.
Kinetic energy may be converted into other types of energy and transported between things. A flying squirrel may run into a chipmunk that is standing still, for instance. Some of the squirrel's original kinetic energy may have been transferred to the chipmunk or changed into another kind of energy after the impact.
To view more about kinetic energy, refer to;
brainly.com/question/2972267
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2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
Letter d, because they are both alkali metals (group one)
