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3 years ago

13

HURRY PLEAS!!!!!!!!!!!!!!!!!!!!

2 answers:

mixas84 [53]3 years ago

8 0

D. action force and reaction forces are stated in his law

Eduardwww [97]3 years ago

7 0

I think it's D.

Good luck :)

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You need a 20% alcohol solution. on hand, you have a 240 ml of a 15% alcohol mixture. you also have 40% alcohol mixture. how muc

juin [17]

0.15*240=36 ml of alcohol in <span>240 ml of a 15% alcohol mixture
0.4x = </span>ml of alcohol in x ml of a 40% alcohol mixture
0.2(x+240)= ml of alcohol in (x+240) ml of a 20% alcohol mixture

0.15*240 + 0.4x = 0.2(x+240)
36+0.4x=0.2x+48
0.2x = 12
x=12/0.2=120/6=20 ml of a 40% alcohol mixture

4 0

3 years ago

What is the molarity of a solution containing 501mL with 35g NaCl

Vesna [10]

Answer:

Data:

mass of solute: 35g of NaCl

m.mass of solute: 58g/mol

volume of solution: 501mL

Molarity=?

Explanation:

501ml = 0.5dm3

M= g of solute/m.mass of solute*vol of solution

M= 35/58*0.5

M=1.20

6 0

3 years ago

Name the two molecules Nн нннн

arlik [135]

Answer:

1: C5H12

2:C5H11

Explanation:

nakqkchlqosnx

4 0

3 years ago

H. Nitrogen gas and hydrogen gas combine to produce ammonia gas (NH3).

DedPeter [7]

Answer:

<u>27.3 L</u>

Explanation:

<u>Reaction</u>

N₂ (g) + 3H₂ (g) ⇒ 2NH₃ (g)
This is the basic reaction at STP

<u>Solving</u>

10 g N₂ x 1 mol NH₃/28 g N₂ x 3 mol H₂/1 mole N₂
⇒ 1.07 mol H₂

V = nRT/P [From Ideal Gas Equation]
V = 1.07 x 62.36 x 298 K / 735
V = <u>27.3 L</u>

4 0

2 years ago

If you mix 50mL of 0.1 M TRIS acid with 60 mL of0.2 M<br> TRIS base, what will be the resulting pH?

Katyanochek1 [597]

<u>Answer:</u> The pH of resulting solution is 8.7

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

<u>For TRIS acid:</u>

Molarity of TRIS acid solution = 0.1 M

Volume of solution = 50 mL

Putting values in above equation, we get:

$0.1M=\frac{\text{Moles of TRIS acid}\times 1000}{50mL}\\\\\text{Moles of TRIS acid}=0.005mol$

<u>For TRIS base:</u>

Molarity of TRIS base solution = 0.2 M

Volume of solution = 60 mL

Putting values in above equation, we get:

$0.2M=\frac{\text{Moles of TRIS base}\times 1000}{60mL}\\\\\text{Moles of TRIS base}=0.012mol$

Volume of solution = 50 + 60 = 110 mL = 0.11 L (Conversion factor: 1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[salt]}{[acid]})$

$pH=pK_a+\log(\frac{[\text{TRIS base}]}{[\text{TRIS acid}]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of TRIS acid = 8.3

$[\text{TRIS acid}]=\frac{0.005}{0.11}$

$[\text{TRIS base}]=\frac{0.012}{0.11}$

pH = ?

Putting values in above equation, we get:

$pH=8.3+\log(\frac{0.012/0.11}{0.005/0.11})\\\\pH=8.7$

Hence, the pH of resulting solution is 8.7

6 0

4 years ago