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andre [41]
3 years ago
11

What are the correct coefficients when this equation is balanced?

Chemistry
1 answer:
larisa86 [58]3 years ago
6 0

4, 3, 1

Explanation:

Sb has four on the right, so it needs four on the left. It's all alone, so <u>4</u>.

O2 comes in pairs, so you only need <u>3</u> of those to get six oxygens.

And 1 is the place holder for the right side since we got the left to match perfectly.

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A.soil acidity affects plant growth
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True or false: water can be pumped into oil reservoirs to increase the pressure of the existing oil.
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Im pretty sure that is true. but the oil will no longer be pure, as it was mixed with water.
7 0
4 years ago
Phosphofructokinase is a four‑subunit protein with four active sites. Phosphofructokinase catalyzes step 3 of glycolysis, conver
svp [43]

Answer:

1. PEP is a feedback inhibitor of phosphofructokinase.

4. PEP inhibition of phosphofructokinase yields a sigmoidal velocity versus substrate curve.

6. The binding of PEP to one phosphofructokinase subunit causes a conformation change that affects the ability of the substrate to bind to the other subunits.

Explanation:

Phosphofructokinase-1, PFK-1, is an allosteric enzymes composed of four protein subunits.

Allosteric enzymes are enzymes that function through non-covalent binding of allosteric modulators which may be activators or inhibitors. They produce a characteristic velocity versus substrate sigmoidal curve. PFK-1 has a separate binding site for its substrate, fructose-6-phosphate and it's allosteric modulators: ATP, ADP or phosphoenolpyruvate, PEP.

The enzyme can exist in two conformations, the T-state (tense) or the R-state (resting). Binding of substrate causes a conformational change from T-state to R-state, whereas binding of allosteric inhibitors returns it to the T-state.

PEP, the product of step 9 in glycolysis, is an allosteric inhibitor of PFK-1. When it binds to the the allosteric site, it leads to conformational changes in PFK-1 from the R-state to the T-state which reduces the enzymes ability to bind the substrate. These changes are responsible for the sigmoidal velocity/substrate curve in allosteric enzymes.

Therefore, the true statements from the options above are 1, 4, 6.

Options 2,3 and 5 are wrong because PEP is a negative effector of PFK-1, thus its binding reduces the affinity of PFK-1 for its substrate. Also, PFK-1 being an allosteric enzyme has separate binding sites for its substrate and its modulators. Thus, there is no competition for active site binding by substrate and modulators.

5 0
3 years ago
Measurements show that the enthalpy of a mixture of gaseous reactants increases by 215. kJ during a certain chemical reaction, w
scoundrel [369]

Answer:

a) ΔU = 370 KJ

b) Endothermic

Explanation:

a)

The change in energy of the mixture can be given by first law of thermodynamics as:

ΔQ = ΔU + W

ΔU = ΔQ - W

where,

ΔQ = change in heat energy of system

ΔU = Change in internal energy of gases

W = Work done on gases = - 155 KJ

For an isobaric process (i.e constant pressure) we know that:

ΔQ = change in enthalpy = ΔH

ΔQ = 215 KJ

Therefore, using values in the equation, we get:

ΔU = 215 KJ - (-155 KJ)

<u>ΔU = 370 KJ</u>

b)

Since, the enthalpy of products is greater than the reactants. Therefore, this is an <u>endothermic reaction</u>.

7 0
4 years ago
Which product is made using bacteria
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