M<PLA = 1/2 m PYA
110 = 1/2 (12x - 20)
12x - 20 = 220
12x = 220 + 20 = 240
x = 240 / 12 = 20
Point- Slope form is
y - y1 = m (x - x1)
m = slope, (x1, y1) = point
Slope intercept form is y = mx + b
m = slope, b = y-intercept
In order for two lines to be parallel, they must have the same slope, so in this case our slope, m = 2. Now use point-slope form to insert the point and solve.
y--2 = 2 (x --5)
y + 2 = 2x + 10
y = 2x + 8
<span>8x+4y+(-8z^2)+[3z+(-5z)] the answer is D</span>
Let's start with the x coordinates.
-8 is on the left, and -4 to the right, so that will help organize this.
the line goes from -8,-9 to -4,-8. it moved 4 over the x axis and rose 1 over the y axis.
rise/run so 1/4 is the slope.
y=(1/4)x - 7
RS points east; R'S' points north, so there has been a rotation 90° CCW.
After that rotation, point S would be at (1, -1). It is actually at (1, 1), so has been shifted 2 units upward.
A sequence that does the desired mapping is
- c. rotation of 90° CCW about the origin
- b. translation 2 units up