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Elenna [48]
3 years ago
7

Town A and town B calculated the number of dogs in each town based on the average number of dogs per neighborhood. The graph bel

ow represents the number of dogs in town A. The equation below represents the number of dogs, y, in town B, where x represents the number of neighborhoods in the town.
y = 10x
Which town has the greater average number of dogs per neighborhood?
A. There is not enough information to determine the average number of dogs per neighborhood.
B. Town A and town B have the same average number of dogs per neighborhood.
C. Town A has the greater average number of dogs per neighborhood.
D. Town B has the greater average number of dogs per neighborhood.
Mathematics
1 answer:
Inga [223]3 years ago
5 0
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Answer as soon as possible
icang [17]

Answer:

  B.  9, 9x, 18x

Step-by-step explanation:

The value in each box is the product of the row heading and column heading. You can find the missing column heading by dividing the box value (162) by the row heading (18).

7 0
4 years ago
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5/8 = 2m + 3/8 <br><br> Please help
DIA [1.3K]
<span>5/8 = 2m + 3/8 
Subtract 3/8 from 5/8
2/8=2m
Divide 2 on both sides
Final Answer: 2/16 or 1/8 *Both answers are equivalent to each other.</span>
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4 years ago
Suppose that 24 inches of wire costs 96 cents.
Alexxx [7]
At the same rate, 31 inches of wire will cost 124 cents.

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2 years ago
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6 0
4 years ago
Anumeha knows the following information about a set of 20 numbers: 9 numbers are a multiple of 3 but not a multiple of 4. 10 num
11111nata11111 [884]
First you need to set up the frequency chart. The columns can be Multiples of 3 and not multiples of 3. The rows can be Multiples of 4 and not multiples of 4 like shown in step 1. in attached file

Then we start adding in values I will add 20 as the total numbers as in step 2 in attached file. 

Next I place in the Multiple of 9 that is not 3, and the total multiples of 3, and total multiples of 4 in step 3.

Based on the totals I can assume that there are 10 that are not multiples of 4 and ten that are not multiples of 3 shown in step 4 

In step 5 I fill in the insides so that the totals will add up so we know that for multiples of 3 9+1=10 so I fill in the one at the top left corner.

In step 6 the only numbers left to fill in the totals would be 9 and 1  for values that are not multiples of 3 and not multiples of both.

Download pdf
5 0
3 years ago
Read 2 more answers
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