Answer:
the solution set is: x < 1
Step-by-step explanation:
Given that:
-6x+5>-1
We have to find solution for x so by simplifying:
Subtracting 5 from both sides we get:
-6x+5 - 5>-1 - 5
Both 5s on left side will be cancelled out:
-6x > -6
Dividing both sides by -6 will change the sign of inequality:
-6x/-6 < -6/-6
x < 1
So the solution set is: x < 1
i hope it will help you!
Answer:
f^-1 (x) = 1+ln( (x-3)/2)
Step-by-step explanation:
hello :
let f(x) = y so : y = 2e^(x-1) +3
calculate x : e^(x-1) = (y-3)/2
for : y-3 > 0 : x-1 = ln( (y-3)/2) so : x= 1+ln( (y-3)/2)
If(x)= 2e^(x-1) +3 , what is f^-1 (x) = 1+ln( (x-3)/2)
Answer:x=10
Step-by-step explanation:x x2
Step-by-step explanation:
Lets assume that angle of right angle trangles are <a,<b and <c
here one of the angle is 90°
so, <a=90°
now,
By the question
<c=3×<b+14
again,
<a+<b+<c=180° (being sum of interior angles of trangles)
90°+<b+(3×<b+14)=180° ( including the value of <a and <c)
90°+<b+3<b+14=180°
4<b=180-90-14
<b=86/4
<b=19°
<c=3×<b+14
=3×19+14
<c=71
smallest angle is 19°
and another small angle is 71°
(x^a)(x^b)=x^(a+b)
(ab)(cd)=(a)(b)(c)(d)
x^-m=1/(x^m)
(3y^-4)(2y^-4)=
(3)(y^-4)(2)(y^-4)=
(6)(y^-8)=
6/(y^8)
